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已知复数z满足eqId5ab4fd800f834c7f8699c562576c45c5(其中i为虚数单位),则eqId89e92a114a864d5598c888ddce53481e(   )
A.eqIdcd9b24a6a6e5426ab775be20461174e3B.eqId5e30b3f3682042e3bf61665ea4945f08C.4D.eqId91f49a316d3f4a459b0af3a7e2686685
eqId31c7ecc992c94f7a962228b648f6be91,则eqId71b066f4ef034bf6b75c671bd9877701=
A.2B.eqIda2a0ce3781fa4c26b624f5966b7dee44C.eqId65021072e3ee4edc934739d219c8c5e2D.1
已知复数eqId8946ee8b0239425d9734457517e0ff5bi为虚数单位,则eqId1d6da3b0763b483ba9bd916b31671a27=(   )
A.eqIde1490df2d2c84688942d45fd01c90a85B.eqId5222c2ea3b544c58bafb590c9238c493C.eqId49b7b111d23b44a9990c2312dc3b7ed9D.eqId5f816d038c584dc7a249120298677ef3
设复数z满足eqId07411e8a0ed64b7ab545c038cc1196e0,i为虚数单位,则下列命题正确的是(    )
A.eqId29aa2a3d095c4e4ebd8f90e304af9ed4B.复数z在复平面内对应的点在第四象限
C.z的共轭复数为eqIdf7a2d5f2819a4df28ae537ec45af5efbD.复数z在复平面内对应的点在直线eqId61790e1fbd804db294d2ec2e5a6c6830
已知i为虚数单位,若eqId2a7054ff05464566839dfa18701d7470,则eqId7636f89217b345e8a250706836dabaaf(   )
A.2B.eqId65021072e3ee4edc934739d219c8c5e2C.1D.eqId5f816d038c584dc7a249120298677ef3
更新:2020/08/11 |题型:单选题 |组卷:389|引用[33]
已知eqIdac8e3b166bed48e78143dd9e8b65f9efeqIdb6e15e51d29a47a7aff44f98b1aafaee为虚数单位),则eqId7636f89217b345e8a250706836dabaaf(   ).
A.eqIdd9014531eb8f4ecfaa1496f0f3b63ac4B.eqId67cbac5d90cc4e0b9f185919908346f6C.eqId5f816d038c584dc7a249120298677ef3D.eqIdc5891f66ccce4fcaa336ab9e7f6f6733
已知eqIdb6e15e51d29a47a7aff44f98b1aafaee为虚数单位,复数eqId6fb7755612244a5cb081563d4934dd7c,则eqId7636f89217b345e8a250706836dabaaf(   )
A.eqId37705e1ef6a84bbdbe88433e75932cdfB.eqId65021072e3ee4edc934739d219c8c5e2C.eqIda2a0ce3781fa4c26b624f5966b7dee44D.eqIdc052ddfbd4524f67a79e0e77c2e5656a
在①eqId9d1fc87164ab4b5f9e020157d081c54c,②复平面上表示eqId6e1a20db661a41649db211dfd18b19e0的点在直线eqIde10cdbf32e9248738ffa9bdc5a1ca05b上,③eqId0eb35a991b554f2a9892c0cb3fa8a55e.这三个条件中任选一个,补充在下面问题中,求出满足条件的复数eqId2cd9e2fe3d6540df9399dbefe49ada54,以及eqId71b066f4ef034bf6b75c671bd9877701.已知复数eqId1a9d5dd621764675a2a0586f8d05d766eqIde15981fbff7d4970aeecae314a80bb0f,______.若eqId82b051d3e55e405f835da6ae736a2975,求复数eqId2cd9e2fe3d6540df9399dbefe49ada54,以及eqId71b066f4ef034bf6b75c671bd9877701.