组卷网>知识点选题>第十二章 算法初步、复数
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3 . 阅读下面问题的解法:
求复数eqId49b8b15348b842c4bc6a8502b48bba82的模的取值范围.
解:eqId99399516b6214b04bc04741253e6b0cc
说明: figure
如图所示,设点A的坐标为eqIdd9602ecef36946b3ac23da447b595759,点B的坐标为eqIdb2ccb3e2610e45488e3db99274db8b78,则eqId22ad563438bc4e1084cdf582fd08deef即为点AB之间的距离eqIdfd44c67ef2814bf3aa0186f0d5ca0cfd
∵点B的轨迹为以O为圆心,半径为1的圆,∴eqId356ceedbbeb9470aa3893b4dcc6f4ae1,因此复数eqId49b8b15348b842c4bc6a8502b48bba82的模的取值范围是eqIdd206017729fb4aebaa165ca2c483fed7
试运用类似上面的解法解下列问题:求函数eqIdd8c1bbb3c2c64cc8b5c8b3e5dcf1051e的值域.
单选题 | 较易(0.85) | 2021·河南高二期末(文)
4 . 执行如图所示的程序框图,若输入的eqId70a27b6ddf6b478285353abb3b1f3741值为eqId29c898c2f6d5480e84ed6cd0dfc0930b,出的eqId70a27b6ddf6b478285353abb3b1f3741值也为eqId29c898c2f6d5480e84ed6cd0dfc0930b,则判断框中可能是(   )
说明: figure
A.eqIda349246042c54d2d8abbd4c4a8ac9676B.eqIda9231567563b43e1a3f420f579c7dfd4C.eqIdf35d49b92c1242bdb9284256f6298535D.eqIda32a559885984562a7f4137ea346f9eb
5 . 已知复数eqIdf291de79cade4cf78846fb9e56b58491eqId3ab705aaaaaf497988a018d92522d28feqId89906913d0754f03a4e4e15e274a9cb1eqId30bb87c3252146748b8c61e7205511b8是虚数单位).
(1)若eqId4b143fb0b6bd48c3b8db24a8a95343f3的实部与eqId4f3b088061b74b91800ceb300f29522b的模相等,求实数eqId70a27b6ddf6b478285353abb3b1f3741的值;
(2)若复数eqId9099627a891b4431ae97992f1a96ea36在复平面上的对应点在第四象限,求实数eqId70a27b6ddf6b478285353abb3b1f3741的取值范围.
单选题 | 较易(0.85) | 2021·河南高一期末
6 . 秤漏是一种特殊类型的漏刻,是用中国秤称量流人受水壶中水的重量来进行计时的仪器.它是北魏道士李兰于eqId8f65c930571d4ff6aa6a50029d46826e世纪发明的.它有一只供水壶,通过一根虹吸管(即古代的渴乌)将水引到一只受水壶(称为权器)中.权器悬挂在秤杆的一端,秤杆的另一端则挂有平衡锤.当流人权器中的水为一升时,重量为一斤,时间为一刻(一斤水对应一“古刻”,相当于eqIde90bfac73c714216b9e4e92afdf57cc8分钟).其基本思想是以供水壶流出的水的重量作为计时标准,以秤杆作为显时系统.如图所示的程序框图为该秤漏的一个计时过程,若输出的eqId69f56ef2c88b4b73a560da59f5247a82值为eqId1f75735d3326439ebe71a2ab52637302,则判断框中应填入(   )
说明: figure
A.eqId638f70edcc474847addc1ec241db86a2B.eqIda77e38449b2940c19d39955240c1f489C.eqId01cdd26a0ebd440c90730f840b5f6c7cD.eqId484137d629b74bfea53a7161cfcf7537
7 . 设复数eqId4f3b088061b74b91800ceb300f29522beqId4b143fb0b6bd48c3b8db24a8a95343f3在复平面内的对应点分别为eqIdeb53cb7cb0274f7d8f111c60f824c243,若点eqId052844cae8574a8ab842c38a039baac0eqId8754ce8cf7f34f04abb9a0c041f57f5c关于实轴对称,且eqId8d68bd5ff56f4f169dd15be12c7e9377,则eqId1f9af61b14bf46c6b91baea738508bb6___________.
单选题 | 容易(0.94) | 2021·河南高二期末(理)
8 . 若复数eqIddd6079668bc1493c98bd9b5e52bc9208eqIdff0e455f0e0444c9b0ba479e95400f1ceqId30bb87c3252146748b8c61e7205511b8为虚数单位)是纯虚数,则实数eqIda4be99d332154d13a4a6ed1ff6444fe7的值为(   )
A.eqId5c1c12d4b3ba4aaab6267324ae66c81eB.eqId8898c1dc81824f3098bbeae74e8f11fdC.eqId3b29afc35d5a4bdfab8a0674ec37b12dD.eqId7f821b32021f4b64b556fc795e3bd450
9 . 若复数eqIda0ece52df5324cddb2fc9dc081e5bd55eqId30bb87c3252146748b8c61e7205511b8为虚数单位),则eqId03848a3da7554cadba483391c0c31853的实部与虚部的差为(   )
A.eqId5c1c12d4b3ba4aaab6267324ae66c81eB.eqIdc052ddfbd4524f67a79e0e77c2e5656aC.eqId29c898c2f6d5480e84ed6cd0dfc0930bD.eqIda86879ae304449a4a6e6461c485a1f13
10 . 执行如图所示的程序框图,则输出的eqId37abcf0d52514fdb9825ab5a3972485a(   )
说明: figure
A.0B.eqIdefe7549d43a142158aee9b47aa9a1354C.eqId7d8eeb211404428fa221eed66dd9e3f2D.eqId1f74afb16b6445758c74277989d159cd