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解答题 | 一般(0.65) | 2021·山东高二期末
1 . 已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqIdc2d3271b09324d98954c33293515c0e9eqId2b68962b28034e54b1a589d87a45c483
(1)求eqId0509add794484602a2c710f41d9ddddceqId5cae532f2168495188622189ec8df62ceqId310274b5ffe34ad58a069683d0dac787,并求eqIdef9cef8e6d054d8dac46b8cde14953ad
(2)求eqId93e38ecd74a24cb59da79181b95bfd3a的前100项和eqId54e424ae93914d4a870f5c8133798fc7
2 . 在数列eqId93e38ecd74a24cb59da79181b95bfd3a中,eqId71a9adf926c44d4d9cdc72fe7ac7c1a8eqIde4d88278ca68458585c9c872bebf2878eqId532dc4d959024b79b546428f5856e5aa),eqIde65b3d775fee4e11998ac3597d4085fb.
(1)求eqId0509add794484602a2c710f41d9ddddceqId5cae532f2168495188622189ec8df62ceqId310274b5ffe34ad58a069683d0dac787
(2)归纳猜想数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式,并证明;
(3)求数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和eqIddb5481de79c946c0a760143297d5eade.
单选题 | 一般(0.65) | 2021·四川高一期末(理)
3 . 在数列eqId93e38ecd74a24cb59da79181b95bfd3a中,已知eqIdc2d3271b09324d98954c33293515c0e9eqIdc1e4d301eec54450bd5d8b768691ec82,且eqId1c4646cb45c9485f9e17cdd6e2294f46等于eqId050bfd2e63e549d78a80dde41c2ff449的个位数eqId13df7239201a414aa2ca0795f0ab583e,若数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId4d2187284c5d4de29906363f7d21f60f项和为2021,则正整数eqId4d2187284c5d4de29906363f7d21f60f的值为(   ).
A.508B.507C.506D.505
4 . 已知eqIddb5481de79c946c0a760143297d5eade是数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和,eqIdc2d3271b09324d98954c33293515c0e9eqId4f31f99fd6324103b946d08e95ff44b9,则eqId2114c5d3dfd04933ab98afa9203b9780______.
5 . 在①eqId9cfea2d311da45488a84ad01481210f8eqId3139665a09d947cf931b747d51808c77;②eqIdc53e6b7f46674c75b59e19f35d4e1d50;③eqIdabe7bddf74ac46a99aa48b17728f6013三个条件中任选一个,补充到下面问题中,并解答.
已知数列eqId054d5a7de5684002909fe944c86227c2的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,满足______.
(1)求数列eqId054d5a7de5684002909fe944c86227c2的通项公式:
(2)数列eqId69fa66742e6b480eb0e55f574b8b7749满足eqIddd4e23ebb2b74532a09d52c1317ff4c8,求数列eqId69fa66742e6b480eb0e55f574b8b7749的前10项和.
注:若选择不同的条件分别解答,则按第一个解答计分.
6 . 已知正项数列eqId054d5a7de5684002909fe944c86227c2的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,对eqId3e824472cf9f4d9bb0657a2101d2a534eqId867e1298b5c847c192b5b10602bd621b.
(1)求数列eqId054d5a7de5684002909fe944c86227c2的通项公式;
(2)若eqId2f444104084043c69e87bb99d5c24dba,求eqId69fa66742e6b480eb0e55f574b8b7749的前项和eqId92ed363a54bd4a8a93df9463bb3af1f5.
7 . 已知数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,且满足eqId36b89dbe737e404788c41b35b1abf6b3eqIddc20157676404c5aaa9c0428dda247d2,其中eqId6fc94f6e181444c6b809fb393eb8fae6
(1)若eqIdd5a6569623204652aada8c497a766e0a,求eqIdef9cef8e6d054d8dac46b8cde14953ad
(2)是否存在实数eqIda9cd3f94eb8045438f75e9daccfa7200eqId072d7d6b911b42bc89207e72515ebf5f使eqIdfc84862e69d44e89bff7695300221de3为等比数列?若存在,求出eqIddb5481de79c946c0a760143297d5eade;若不存在,请说明理由.
解答题 | 较易(0.85) | 2022·全国高三专题练习
8 . 设数列eqId2c1230a9ef5a4968be599681d676dd2b满足eqIdb788e8061ddb485cafe3b9f734188a8d,且eqIde65b3d775fee4e11998ac3597d4085fbeqIdf0e3f623108c47289072bcf3d6d1d7b4.
(1)求eqId0509add794484602a2c710f41d9ddddceqId5cae532f2168495188622189ec8df62c的值;
(2)已知数列eqId2c1230a9ef5a4968be599681d676dd2b的通项公式是:eqId9f3c7f5b844d45209a538c9ebafd461aeqId97e60ec70ae44b0d8ea479ba94c74696eqIde7c5bd138681423fad3592709fd71835中的一个,判断eqId2c1230a9ef5a4968be599681d676dd2b的通项公式,并求数列eqId7f0b835051c24d5aa50c31679348a83a的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和eqIddb5481de79c946c0a760143297d5eade.
更新:2021/08/02组卷:0
9 . 已知eqId93e38ecd74a24cb59da79181b95bfd3a是公差不为零的等差数列,eqIdd3e3914b3c124e6aa8bbee4397612779eqId75691f28a5bb4c8287401017aa3a2d29eqId310274b5ffe34ad58a069683d0dac787的等比中项.
(1)求数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式;
(2)令eqId0e87caa2e16545a59aa076f701c283c4,设eqId816e3bc6a7914e19a94ded170b87b62d,求数列eqId74ef5fe5183946caaee41d8974816a20的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和eqId92ed363a54bd4a8a93df9463bb3af1f5.
解答题 | 一般(0.65) | 2022·全国高三专题练习
10 . 已知eqId93e38ecd74a24cb59da79181b95bfd3a是等差数列,其前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eadeeqIdeeb4ca98872f4e6d91cea28f43fc0b63是正项等比数列,且eqIde8c5839638aa4f79942fefdb4207ae82eqIdb73e938a3cf744909e7084a95cba0178eqId7c54af47a9ab4a199bd5e545c124f0ffeqId3e7bfd2df7c245a595e2787ebf6d784e
(1)求数列eqId93e38ecd74a24cb59da79181b95bfd3aeqIdeeb4ca98872f4e6d91cea28f43fc0b63的通项公式;
(2)若eqId5300e754d5d540788122a05f536cbb15,记eqId589b1ee61ca94239b3e71bd5faa2287feqId6c2146ec6df54fc9af9b2aef04489c8b,求eqId88aaf74af4f04005a15fd8aa2f78aa50.
更新:2021/07/31组卷:0
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