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1 . 已知数列{an}的前n项和Sn=2n+2﹣4(nN*),函数fx)对∀xRfx)+f(1﹣x)=1,数列{bn}满足eqId97dc36fd4d3249c79c00eeab8629076c+feqId28ff46377eee4336bfc051da515580bb+f(1).
(1)分别求数列{an}、{bn}的通项公式;
(2)已知数列{cn}满足cnanbn,数列{cn}的前n项和为Tn,若存在正实数k,使不等式kn2﹣9n+49)Tn>10n2an对于一切的nN*恒成立,求k的取值范围.
2 . 已知eqId8b7c00f7c0d548b1b0b5814534163f85eqId7dcd2312d0bf4bb1befdfcc170e45791上的奇函数,则函数eqIde4a0e3706b56447b90fe1b2781f91b14的图像关于点__________对称;若eqId7d5ba242c4b94a979d7b08a872fc9e36eqId6c2146ec6df54fc9af9b2aef04489c8b),则eqIdd685e0a0c5ae467c879ef2ec3214a2fa__________.
单选题 | 一般(0.65) | 2020·镇江崇实女子中学高三月考
解题方法
3 . 已知函数eqIdacf514fa82dc4abb9a12b4a567505fa6,数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId3a09f1dd8f1e4c0ba93f224f2878fd76,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的前2019项和为(   )
A.eqIde73304e2b5f644a8a94ec5bb1c8c0d13B.1010C.eqId2b625d6a376f4789b74d6e99c255a2c4D.1011
4 . 已知eqId21b69ff2081f4a22b29e33b68570ffc4
(1)若eqId94e1a0c36f9f478ebffe9e894d1585b0,求eqId92cb82a2c0354749b5125e21e5afbe86
(2)若eqId83223c91363d4b34b48313be8ec2e0cf,求eqId2e34926016d14578af98e00bddbfa709除以5的余数
单选题 | 一般(0.65) | 2021·四川高三二模(文)
解题方法
5 . 已知函数eqIdbe929572b234476aa1adc18f19acf421,则eqIded9d9b3160454adf83843c4d938e1030的值为(   )
A.1B.2C.2020D.2021
解答题 | 一般(0.65) | 2020·苏州大学附属中学高二期末
6 . 设eqIdd083ab0d56df45c388700271956a70ebeqIdc27f89d973914990bcb46021992dae6d是函数eqId0d216e38734c47e89010947accb2ff73的图象上的任意两点.
(1)当eqId3ed7954680fb4549afc0044a4b3d39c3时,求eqId2a32abc17ff84ebca1a569a5957ea4dd的值;
(2)设eqIddb42e1e59d584ebd9649957266de1921,其中eqIdc73ad4de0ec14cba91db08ec61124907,求eqIddb5481de79c946c0a760143297d5eade
(3)对应(2)中eqIddb5481de79c946c0a760143297d5eade,已知eqId91ad2d842d4344949519c7afc8a24cd6,其中eqIdc73ad4de0ec14cba91db08ec61124907,设T为数列eqId6a8c58e9235340f0acd6636807738649的前n项和,求证eqIdbe5a1e8e81ce4059915e9f4a31ebf1d4
填空题 | 一般(0.65) | 2020·桃江县第一中学高三期中
解题方法
7 . 已知函数eqId771c4302e0c14da19350f3a09e1910b3,数列eqId93e38ecd74a24cb59da79181b95bfd3a是正项等比数列,且eqIdb95c79cc2e5746ad801007411919942eeqId91ec8aefb4f649e3a3f4dc3b84789a75________.
8 . 对于数列eqId93e38ecd74a24cb59da79181b95bfd3a,定义数列eqIdd0f23d3ccaf94a0cac3db2f560f94ab9为数列eqId93e38ecd74a24cb59da79181b95bfd3a的“差数列”,若eqId77b3f6b9955e499dbdab033a38779496eqId93e38ecd74a24cb59da79181b95bfd3a的“差数列“的通项公式为eqId9cfea2d311da45488a84ad01481210f8,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId92478644b29a4a0e8470a8c89d31b49f项和eqIde1c97d4ea27f4811a53f3dbddb5cae9e___________.
解题方法
同步
9 . 已知函数eqIdd1ef5a6630b84b4e9720b870365d6417,利用课本中推导等差数列的前eqId92478644b29a4a0e8470a8c89d31b49f项和的公式的方法,可求得eqId642e91d1f9aa4de082a047cba487e6c1eqIdcb90de6ec22f4633b7d5f8c2275c99b1(   ).
A.25B.26C.13D.eqId25442d2465094afa86b8351c10b8bd9d
10 . 已知数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId92478644b29a4a0e8470a8c89d31b49f项和为eqIddb5481de79c946c0a760143297d5eade,满足eqId23864497b5824a8e89d5f56b96a665ed,(eqId4959a8a13c0b40f3a3b076626a4b616c均为常数),且eqId06d48362fca9438897d2ccd4b42f96be.设函数eqId3ca3073af1954e758bc7f01727eab98f,记eqIdc8b17492eb054e4f90b4450799c9294a,则数列eqId1ac93069713a41bf9a9b85f6f21fcabc的前eqId0bad15ca833c426894079a104ff88a36项和为(   )
A.eqId306c7e72188c47128a7415bebb5b8ef2B.eqId479b532b33d94202bcd4cf3bd8f3bbdfC.eqIdecb828cf922546bb9760e0ce5c95a9cbD.eqId0bad15ca833c426894079a104ff88a36
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