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填空题 | 一般(0.65) | 2021·广东高二期末
解题方法
1 . 若eqId3bb3bb9088eb433a91eddc91d48bda70eqId617427d7f53746aabb2b5f336d7dce75的图象有且仅有两个公共点,则实数a的取值范围为_____.
2 . 设函数eqIda9749332a05e4b37b19cd5b9e0c9eb18.
(1)当eqId353d918c839747d0a59b7c6bd24f35e8时,求eqId10852d81bc184140a7780250c82c6929eqId90f4010cc71b4998be6fa90952078f6b处的切线方程;
(2)若f(x)在eqIdbe1458080a8c442fbbc83863be99bb06上有且只有一个零点,求实数eqIda4be99d332154d13a4a6ed1ff6444fe7的取值范围.
单选题 | 较易(0.85) | 2021·重庆复旦中学高二期中
解题方法
3 . 若函数eqIdb10101b4b67747738bd2593fd1e743f7eqId59c0250ba5004a0995f2c662420fa8ab图象恰有一个公共点,则实数a不可能取值为(   )
A.2B.0C.1D.eqId40dc3382431b4d6590c0446bc96ba770
单选题 | 较易(0.85) | 2021·全国高二课时练习
解题方法
同步
4 . 若函数eqId144eff5c0e4649138a21f2b1b6a06907的导函数eqId67275592f85f400ab271f455b71d45c3的图象如图所示,则函数eqId144eff5c0e4649138a21f2b1b6a06907的图象可能是(   )
说明: figure
A.说明: figureB.说明: figure
C.说明: figureD.说明: figure
更新:2021/08/02组卷:13
5 . 己知函数eqId9b37d03e47a347fc8fab9f814ba5fac4的导函数eqIdd26cd9f8ad374ae192a20aada45c1618的图象如图所示,则下列判断正确的(   )
说明: figure
A.eqId10852d81bc184140a7780250c82c6929eqId1a796752c3044bc28a044feb53df36ff时取极小值B.eqId10852d81bc184140a7780250c82c6929eqId8e222b35ffdc4871a6a47ee7ddc18b42时取极大值
C.eqId4d4fdac30a74427181eebc5dd20dc113eqId10852d81bc184140a7780250c82c6929极小值点D.eqIdbf6df677a4ad4645b9eb2dfab9d3230feqId10852d81bc184140a7780250c82c6929极小值点
6 . 方程eqId23106fee2b62451b80bce151879838e7解的个数为(   )
A.3B.2C.1D.0
7 . 定义在eqId7dcd2312d0bf4bb1befdfcc170e45791上的函数eqId6f13759e937144069819aed2ae5a1057,其导函数为eqId1bcbf2adc7b949e6bda2361455eed50b,且函数eqIdda540d115ed34141b467ea45ec72bcd6的图象如图所示,则(   )
说明: figure
A.eqId6f13759e937144069819aed2ae5a1057有极大值eqId3fe56b4f768545d69e1d2d91cb7eac37和极小值eqIdb1fdf83e6d504e3eb8d3c1bd74825b60
B.eqId6f13759e937144069819aed2ae5a1057有极大值eqIdc0c63a3348734268b53aae3c0130e5b9和极小值eqIdb1fdf83e6d504e3eb8d3c1bd74825b60
C.eqId6f13759e937144069819aed2ae5a1057有极大值eqId3fe56b4f768545d69e1d2d91cb7eac37和极小值eqIdc0c63a3348734268b53aae3c0130e5b9
D.eqId6f13759e937144069819aed2ae5a1057有极大值eqIdc0c63a3348734268b53aae3c0130e5b9和极小值eqId3fe56b4f768545d69e1d2d91cb7eac37
8 . 函数eqId164ab17b78c94b408b128f22cfa0fc73eqId870a542425dc497587ed889196105781上的最大值为2,则eqId70a27b6ddf6b478285353abb3b1f3741的取值范围为(   )
A.eqIde86a1b132d2e4c2095d12f23acd88db3B.eqId1d05750b2e214d0b9a9bc9aa567ff5b9C.eqId447e99dfb6624262be283c7b9abff193D.eqId379e0b8721724024be217be3d9e09aef
10 . 若函数eqIde93304cce3c94001a36539de9449b9f4有极值点eqId735b8047beee4dee870fc72ae837a245eqIdecaaaffea9af458c8e6dff16f15c1a73eqId823c4018c0ec4f16a3db3522c291e431,若关于eqIda9cd3f94eb8045438f75e9daccfa7200的方程eqId986c3d59096c4a1384a493f82ff02dfc的不同实数根的个数是(   )
A.6B.5C.4D.3
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