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3 . 在eqId64b9b599fdb6481e9f8d9a94c102300b中,角eqId10bbe48f886a4fa78fdf8c1fd064f9b4的对边分别为eqId0ce93bfa1f6a4a23b3258410dd19847a,若eqId722ac68e14a14415ba81355156534970,且eqId142fb6f8712a4e04a73b56741b7207aa.
(1)求角eqId8754ce8cf7f34f04abb9a0c041f57f5c的值;
(2)若eqId4d9b32ba2f5e40bd850f21cafb963406,且eqId64b9b599fdb6481e9f8d9a94c102300b的面积为eqId62f2412997424b4ca41272f35d432557,求eqId0627be51821d4be7b3e024a354815d64边上的中线eqId53a7c4063fbf45faa9aa214bf50dfdec的长.
解答题 | 一般(0.65) | 2021·全国高三专题练习
解题方法
4 . 已知eqId2b3115bb59e9460691b73621d1e82b44,求eqIdedb1cea1eab14281a86243c3cd616ccd的取值范围.
6 . 在eqId64b9b599fdb6481e9f8d9a94c102300b中,角eqId052844cae8574a8ab842c38a039baac0eqId8754ce8cf7f34f04abb9a0c041f57f5ceqId19a4eb16029e4550a14f2afe4741a3c3所对的边分别为eqId70a27b6ddf6b478285353abb3b1f3741eqIdaea992e70d4943e49e893817eb885ed7eqId44925af6fb19413689ba5616e3647cba,若eqId1e9773437d10473885b6b62df03097d6,则eqId64b9b599fdb6481e9f8d9a94c102300b的形状一定是(   )
A.等腰直角三角形B.直角三角形C.等腰三角形D.等边三角形
填空题 | 一般(0.65) | 2021·江苏苏州中学高一月考
8 . 在eqId64b9b599fdb6481e9f8d9a94c102300b中,内角eqId052844cae8574a8ab842c38a039baac0eqId8754ce8cf7f34f04abb9a0c041f57f5ceqId19a4eb16029e4550a14f2afe4741a3c3所对的边分别为eqId70a27b6ddf6b478285353abb3b1f3741eqIdaea992e70d4943e49e893817eb885ed7eqId44925af6fb19413689ba5616e3647cba,若eqId7d89e33adc274e36b572b05e35635abeeqId64b9b599fdb6481e9f8d9a94c102300b的面积为eqIdec7683a5927343128d62b3a347f3a282,且eqIdde3d422df1a74b1eaec92a797231adc7,则eqId03caad606ae3430f85a4a4e000ef6812__________
解答题 | 较难(0.4) | 2022·上海高三专题练习
9 . 如图,有一景区的平面图是一个半圆形,其中O为圆心,直径eqId99a3187c2b8f4bcc9703c74c3b72f1f3的长为eqId1088f822aec042c4ad308e54b4e1572fCD两点在半圆弧上,且eqId743e23514a934d048ccf429ea0112a94,设eqId7a8927c2394e4531960002237427741d
说明: figure
(1)当eqId5072800bc1de4dbaab8af5571825631c时,求四边形eqId5ce7a06ae7a34393b92b5277978ac014的面积.
(2)若要在景区内铺设一条由线段eqId99a3187c2b8f4bcc9703c74c3b72f1f3eqId0627be51821d4be7b3e024a354815d64eqId34c6b6e427744abfb88dc90b8c7c2111eqId890174c35d994035b942963f9fddd43b组成的观光道路,则当eqId6c9518e43fd5459798a30cfc10026e3c为何值时,观光道路的总长l最长,并求出l的最大值.
10 . 已知正弦三倍角公式:eqId4964779bd1c747bcae1359a273920c85
(1)试用公式①推导余弦三倍角公式(仅用eqId1db75b7c812245c7aa557a2b1ab97dec表示eqIdd6fc2f39f90544b49b072ee75b0c0a35);
(2)若角eqIdc13953f2514e4c8f9c8aaaf5241c33ac满足eqIdb6a9a50b5d144fa08c262a3c599ed7a7,求eqId8b9feebdbbff4551886ca2057e034896的值.