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2 . 已知函数eqId10852d81bc184140a7780250c82c6929eqId7dcd2312d0bf4bb1befdfcc170e45791上的偶函数,对任意eqId735b8047beee4dee870fc72ae837a245eqId6ae412f37b494444bdaa9ac6c704a104,均有eqIdcce5a272657b4018812813a6f1245efa成立,若eqIdca6aeda2d6d1469b952c0b4507e7b9adeqIdecc2690863da4920a3750c814480f8e8eqIdaf61dd6d96a04ced890a885113c8505c,则eqId70a27b6ddf6b478285353abb3b1f3741eqIdaea992e70d4943e49e893817eb885ed7eqId44925af6fb19413689ba5616e3647cba的大小关系是(   )
A.eqId45615ef0900647268b98d1d5eeb28a58B.eqIde20b3cdceb054975bbbb3a4598602bafC.eqIdde23c9bee5f2497a98f967afa9b73a7aD.eqId0d0cc8a6003c4e21bacd608a53c711cf
4 . 设eqId9f2681f29f614a8b9400abb1ac21b4b1,记eqIde64a0c4e4bfd40f19d07fb086204ef9eeqIdf662b58187de498abf9c26376bbc3c84eqId5ce1b97b05934f859f28a49013b09869,则比较eqId70a27b6ddf6b478285353abb3b1f3741eqIdaea992e70d4943e49e893817eb885ed7eqId44925af6fb19413689ba5616e3647cba的大小关系为(   )
A.eqIdde23c9bee5f2497a98f967afa9b73a7aB.eqId98df60d61acf40a38ea6e88af8316379C.eqId45615ef0900647268b98d1d5eeb28a58D.eqId2cf6c501fcaf451c89bbbe8a7b5da7ad
5 . 已知eqId982da3835b7946d999cc8604a2ece266,且eqIdd951487aa2c84adebbd85d63425e0e52eqIdde9050e5536443e8a2531be4df893837,比较eqIdc0496bc0cfbd4c49af4180c1b0f4e9faeqIdbbd1b6f04faf4452a42782498c62b3ba的大小.
6 . 已知eqId606d21f35a9f4728bfeb95741e096209,则eqId8dd4dde3c5624b63a0fd981ca2f6555aeqId92a471cc08e9466bac36a8580672a982eqIdf9b7ae2bde9149a4a1f9419ae885ac61的大小关系是(   )
A.eqIdab89e7649112447b967d5d5a3e82ca38B.eqIdc496edde0e4f4ad586c3b65de574dfa5
C.eqIda295d540c8bc497aa86b75edc06d35c9D.eqIdcdbc1a75c73b483d98cd71ba89c74d5f
7 . 已知eqId70a27b6ddf6b478285353abb3b1f3741eqIdaea992e70d4943e49e893817eb885ed7为实数,则“eqIda3fb368b473b4e71ba3819b356c2695b”是“eqIda9515621315c47b2ad3fb61309fb6f8a”的(   )
A.充分不必要条件B.必要不充分条件
C.充要条件D.既不充分也不必要条件
8 . 对任何eqId7e017f1b4ec24fbb94e05444c41d3d80,都有(    )成立.
A.eqId8060792f2b1d4a32ad53c6ba7ef42e9bB.eqId7ebf2c63797a4c6ebea81df4c6ad4f95
C.eqId86fdb5d38e0f47f0a5de73ca35aaab43D.eqId77a8317822ee4fada552e1d9b0451a61
单选题 | 容易(0.94) | 2021·贵州(文)
9 . 设a=e0.01b=logπec=lneqIdbaf1cd95ee90463db534bb7b55b1e25d,则(   )
A.a>c>bB.a>b>cC.b>a>cD.c>a>b