题型:解答题-问答题
难度:0.65
引用次数:2995
题号:6538435
如图,已知
,BE平分∠ABC,DE平分∠ADC,∠BAD=80°,试求:
(1)∠EDC的度数;
(2)若∠BCD=n°,试求∠BED的度数.(用含n的式子表示)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b0fff774b4b0087a6f304ce930d359be.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/10/7/58e854ee-ba75-4076-9d19-4960b0a0cd72.png?resizew=203)
(1)∠EDC的度数;
(2)若∠BCD=n°,试求∠BED的度数.(用含n的式子表示)
更新时间:2017-05-31 21:51:01
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解答题-证明题
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适中
(0.65)
【推荐1】如图,直线,点
在直线
上,点
在直线
上,点
在直线
,
之间.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/20/fb010cf3-6f9c-4bb0-ae56-5ea5fe36dd5c.png?resizew=424)
(1)如图
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bdaa19de263700a15fcf213d64a8cd57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/95dc55c27ca4f2add4d62278ed447f53.png)
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(2)如图
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/589786dd7c3a2679c3230b671cd232d6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1b9027cd6d428a7fc53107e1cb06aab8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f4c46b6da1f5f076ac224d316233893.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/589786dd7c3a2679c3230b671cd232d6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73465a1f9aa03481295bf6bd3c6903ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d9c1e0c3cab6b7bb3229221f4310ab0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/50e8c257f5615d30660cef4157c6b273.png)
(3)如图
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5634a208294350f8ec151cd19b6d3278.png)
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(直接写出结果)
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解答题-证明题
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名校
【推荐2】根据下列叙述填依据.
(1)已知如图1,
,求∠B+∠BFD+∠D的度数.![](https://staticzujuan.xkw.com/quesimg/Upload/formula/192299b58e20741c0d74a8b46e62c429.png)
所以∠B+∠BFE=180°( )
因为
、
(已知)
所以 ( )
所以∠D+∠DFE=180°( )
所以∠B+∠BFE+∠D=∠B+∠BFE+∠EFD +∠D=360°
(2)根据以上解答进行探索.如图(2)(3)AB
EF、∠D与∠B、∠F有何数量关系(请选其中一个简要证明)
备用图:
EF,∠C=90°,∠
与∠
、∠
有何数量关系(直接写出结果,不需要说明理由)
(1)已知如图1,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b0fff774b4b0087a6f304ce930d359be.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/192299b58e20741c0d74a8b46e62c429.png)
所以∠B+∠BFE=180°( )
因为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b0fff774b4b0087a6f304ce930d359be.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/192299b58e20741c0d74a8b46e62c429.png)
所以 ( )
所以∠D+∠DFE=180°( )
所以∠B+∠BFE+∠D=∠B+∠BFE+∠EFD +∠D=360°
(2)根据以上解答进行探索.如图(2)(3)AB
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/638537c0a30676c73fea76c80e0f8bd0.png)
备用图:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/638537c0a30676c73fea76c80e0f8bd0.png)
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解答题-作图题
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适中
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【推荐1】在如图所示的网格纸中,点
,
,
都在网格点上,请仅用无刻度的直尺按下列要求作图.
中过点
画
的垂线
,且点
在网格点上.
(2)在图
中画
,再画
,且点
,
都在网格点上.
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
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(2)在图
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解答题-证明题
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适中
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【推荐2】根据解答过程填空:
已知:如图,
,
,求证:
.
证明:
,(邻补角互补)
又
,(已知)
,(同角的补角相等)
___________,
__________,
,(已知)
_______,
,( )
.( )
已知:如图,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1d1717b5311ed602f1730e86d9322647.png)
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证明:
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又
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解答题-证明题
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【推荐3】叙述三角形内角和定理并将证明过程填写完整.
定理:___________________________________________________.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/4/19/ffcd0b16-0b87-4126-b6ac-e1e1f2541cc5.png?resizew=197)
已知:△ABC.求证:∠A +∠B+∠C=180°.
证明:作边BC的延长线CD,过C点作CE∥AB.
∴∠1=∠A(__________),
∠2=∠B( _____________),
∵∠ACB+∠1+∠2=180°( ____________),
∴∠A+∠B+∠ACB=180°(_____________).
定理:___________________________________________________.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/4/19/ffcd0b16-0b87-4126-b6ac-e1e1f2541cc5.png?resizew=197)
已知:△ABC.求证:∠A +∠B+∠C=180°.
证明:作边BC的延长线CD,过C点作CE∥AB.
∴∠1=∠A(__________),
∠2=∠B( _____________),
∵∠ACB+∠1+∠2=180°( ____________),
∴∠A+∠B+∠ACB=180°(_____________).
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