如图,AB∥CD,射线AE交CD于点F,若∠1=115°,则∠2的度数是( )
![](https://img.xkw.com/dksih/QBM/editorImg/2023/11/20/35ae9bb0-886b-4781-9d97-58ed6f77ba82.jpg?resizew=146)
A.55° | B.65° | C.75° | D.85° |
更新时间:2020-05-07 16:54:14
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【知识点】 根据平行线的性质求角的度数解读
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【推荐1】将直角三角板按照如图方式摆放,直线a∥b,∠1=130°,则∠2的度数为( )
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【推荐2】如图,直线
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所截,
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的度数为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5c4cd264c97c1f261229925cc5a6761.png)
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A.![]() | B.![]() | C.![]() | D.![]() |
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