已知二次函数y1=ax2+bx+c(a≠0)的图象经过三点(1,0),(﹣3,0),
.
(1)求二次函数的解析式;
(2)若(1)中的二次函数,当x取a,b(a≠b)时函数值相等,求x取a+b时的函数值;
(3)若反比例函数
(k>0,x>0)的图象与(1)中的二次函数的图象在第一象限内的交点为A,点A的横坐标为x0满足2<x0<3,试求实数k的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/acf84052b8ea411842f61c1f90b75fcc.png)
(1)求二次函数的解析式;
(2)若(1)中的二次函数,当x取a,b(a≠b)时函数值相等,求x取a+b时的函数值;
(3)若反比例函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c9d43d1832f4586f5da39dbc9e1854d2.png)
19-20九年级下·天津·期末 查看更多[2]
更新时间:2020-05-29 05:55:20
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【推荐2】如图1,抛物线C1:y=ax2﹣2ax+c(a<0)与x轴交于A、B两点,与y轴交于点C.已知点A的坐标为(﹣1,0),点O为坐标原点,OC=3OA,抛物线C1的顶点为G.
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(1)求出抛物线C1的解析式,并写出点G的坐标;
(2)如图2,将抛物线C1向下平移k(k>0)个单位,得到抛物线C2,设C2与x轴的交点为A′、B′,顶点为G′,当△A′B′G′是等边三角形时,求k的值:
(3)在(2)的条件下,如图3,设点M为x轴正半轴上一动点,过点M作x轴的垂线分别交抛物线C1、C2于P、Q两点,试探究在直线y=﹣1上是否存在点N,使得以P、Q、N为顶点的三角形与△AOQ全等,若存在,直接写出点M,N的坐标:若不存在,请说明理由.
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(1)求出抛物线C1的解析式,并写出点G的坐标;
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【推荐3】在平面直角坐标系中,已知抛物线y=ax2﹣2ax﹣3a(a是常数,且a>0).
(1)该抛物线的对称轴是 ,恒过点 .
(2)当﹣2≤x≤2时,函数的取值范围是﹣4≤y≤b,求a、b的值.
(3)当一个点的横纵坐标都为整数时,称这个点为整点,若该函数图象与x轴围成的区域内有6个整点(不含边界)时,求a的取值范围.
(4)当a=1时,将该抛物线在0≤x≤4之间的部分记为图象G.将图象G在直线y=t(t为常数)下方的部分沿直线y=t翻折,其余部分保持不变,得到新图象Q,设Q的最高点、最低点的纵坐标分别为y1、y2,若y1﹣y2≤6,直接写出t的取值范围.
(1)该抛物线的对称轴是 ,恒过点 .
(2)当﹣2≤x≤2时,函数的取值范围是﹣4≤y≤b,求a、b的值.
(3)当一个点的横纵坐标都为整数时,称这个点为整点,若该函数图象与x轴围成的区域内有6个整点(不含边界)时,求a的取值范围.
(4)当a=1时,将该抛物线在0≤x≤4之间的部分记为图象G.将图象G在直线y=t(t为常数)下方的部分沿直线y=t翻折,其余部分保持不变,得到新图象Q,设Q的最高点、最低点的纵坐标分别为y1、y2,若y1﹣y2≤6,直接写出t的取值范围.
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