题型:单选题
难度:0.4
引用次数:679
题号:11983659
二次函数y=ax2+bx+c(a≠0)的图象如图所示,下列结论:①abc>0;②2a+b=0;③m为任意实数,则a+b>am2+bm;④a﹣b+c>0;⑤若ax12+bx1=ax22+bx2,且x1≠x2,则x1+x2=2.其中正确的有( )
![](https://img.xkw.com/dksih/QBM/2020/12/20/2618001314209792/2624430260322304/STEM/990302c8d36847de8bdb0a25e0e3af93.png?resizew=169)
![](https://img.xkw.com/dksih/QBM/2020/12/20/2618001314209792/2624430260322304/STEM/990302c8d36847de8bdb0a25e0e3af93.png?resizew=169)
A.①②③ | B.②④ | C.②⑤ | D.②③⑤ |
更新时间:2020-12-29 07:59:56
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【知识点】 二次函数图象与各项系数符号解读
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【推荐1】函数
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为常数)的图象如图所示,如果
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A.![]() | B.![]() | C.![]() | D.![]() |
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单选题
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较难
(0.4)
名校
【推荐2】已知抛物线y=ax2+bx+c(a≠0)的对称轴是直线x=1,与y轴的交点在(0,2),(0,3)之间(包含端点),其部分图象如图所示,则,①abc<0;②4a﹣2b+c<0;③若A(﹣
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A.6 | B.5 | C.4 | D.3 |
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