尺规作图(不写作法,保留作图痕迹)已知
,
(1)作一个角等于
;
(2)作
的平分线.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d7b2fe01a33c4825f9974ed9663a99c.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/10/23/b60793aa-c640-405d-ac8c-d5ff44e13c76.png?resizew=139)
(1)作一个角等于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d7b2fe01a33c4825f9974ed9663a99c.png)
(2)作
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d7b2fe01a33c4825f9974ed9663a99c.png)
更新时间:2023-10-21 21:53:30
|
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解答题-作图题
|
较易
(0.85)
【推荐1】如图,在菱形
中,点E在对角线
上,点F为
上一点,连接
.已知点P在边
上,以
为边,请用尺规作图法在
上求作一点Q,使得
.(保留作图痕迹,不写作法)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8cb484a97f28f8b0c9aa27bc051cb5f7.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/3/a1e07f35-8322-4ba5-82d5-853b3fcb2898.png?resizew=171)
您最近一年使用:0次
解答题-作图题
|
较易
(0.85)
【推荐2】如图,点C,O在直线
上,
是一条射线,利用尺规作
,使得
.(不写作法,保留作图痕迹)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
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您最近一年使用:0次
解答题-作图题
|
较易
(0.85)
名校
【推荐1】如图,已知
,
,
.
![](https://img.xkw.com/dksih/QBM/2020/12/9/2610512639401984/2614871725998080/STEM/d7ee664a-6cd8-4f75-98a7-db4897110a25.png?resizew=173)
(1)用直尺和圆规按下列要求作图:(保留作图痕迹,用黑色签字笔加粗加黑)
作
的角平分线
交
于
;
过
点作
垂直于
,垂足为
,
交
的延长线于点
;
(2)证明:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b10134e7a46e6f6f7cb9d5e2371727d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed10df4140819d5451773a45de66201b.png)
![](https://img.xkw.com/dksih/QBM/2020/12/9/2610512639401984/2614871725998080/STEM/d7ee664a-6cd8-4f75-98a7-db4897110a25.png?resizew=173)
(1)用直尺和圆规按下列要求作图:(保留作图痕迹,用黑色签字笔加粗加黑)
作
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
过
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68a83fdd2ba72a2dba0b6b10bb3e06b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68a83fdd2ba72a2dba0b6b10bb3e06b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
(2)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4f654fde982fac75cc3f7a24a082c7b.png)
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解答题-作图题
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较易
(0.85)
【推荐2】下面是小丽同学设计的“作30°角”的尺规作图过程.
已知:如图1,射线OA.
求作:∠AOB,使∠AOB =30°.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/5/9b72da54-fbb7-41a1-9b33-cc2e76c12475.png?resizew=235)
作法:如图2,
①在射线OA上任取一点C;
②分别以O,C为圆心,OC长为半径作弧,两弧在射线OA的上方交于点D,作射线OD,并连接CD;
③以O为圆心,任意长为半径作弧,分别交射线OA,OD于点E,F;
④分别以E,F为圆心,以大于
的同样长为半径作弧,两弧在∠AOD内部交于点B;
⑤作射线OB;
∴ ∠AOB就是所求的角.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/5/b0a18437-c37c-4f41-8c44-2fd669dc98df.png?resizew=211)
根据小丽设计的尺规作图过程,解答下列问题:
(1)使用直尺和圆规,依作法补全图2(保留作图痕迹);
(2)补全下面证明过程:
证明:连接BE,BF.
∵ OC=OD=CD,
∴ △OCD是等边三角形.
∴∠COD= °.
又∵ OE =OF,BE = BF,OB=OB,
∴ △OEB≌△OFB( )(填推理依据).
∴ ∠EOB=∠FOB( )(填推理依据).
∴ ∠AOB =
=30°.
∴∠AOB就是所求的角.
已知:如图1,射线OA.
求作:∠AOB,使∠AOB =30°.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/5/9b72da54-fbb7-41a1-9b33-cc2e76c12475.png?resizew=235)
作法:如图2,
①在射线OA上任取一点C;
②分别以O,C为圆心,OC长为半径作弧,两弧在射线OA的上方交于点D,作射线OD,并连接CD;
③以O为圆心,任意长为半径作弧,分别交射线OA,OD于点E,F;
④分别以E,F为圆心,以大于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/52d092504d3c33c48be43f23b788efd9.png)
⑤作射线OB;
∴ ∠AOB就是所求的角.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/5/b0a18437-c37c-4f41-8c44-2fd669dc98df.png?resizew=211)
根据小丽设计的尺规作图过程,解答下列问题:
(1)使用直尺和圆规,依作法补全图2(保留作图痕迹);
(2)补全下面证明过程:
证明:连接BE,BF.
∵ OC=OD=CD,
∴ △OCD是等边三角形.
∴∠COD= °.
又∵ OE =OF,BE = BF,OB=OB,
∴ △OEB≌△OFB( )(填推理依据).
∴ ∠EOB=∠FOB( )(填推理依据).
∴ ∠AOB =
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d7992470ad772590044202be3cea9449.png)
∴∠AOB就是所求的角.
您最近一年使用:0次