如图,直线
,
交于点
,
平分
,
,
![](https://img.xkw.com/dksih/QBM/editorImg/2024/2/19/f15e2251-cc91-4f32-8ac0-c5a59be04c61.png?resizew=250)
(1)若
,求
的度数;
(2)若
,求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6cad4595d5352b2884568a59d8d766a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dc9f91270ddbe1cf3c1362e1b95aee14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e615356a4d004cc892512c35c4385e55.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/2/19/f15e2251-cc91-4f32-8ac0-c5a59be04c61.png?resizew=250)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09991e988d25cce59ae2573978babcdc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/843adec8fba1741ccb81a9017cfb815f.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5835ddc1c240af4a7748b521b6d68ffa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/843adec8fba1741ccb81a9017cfb815f.png)
更新时间:2024-02-19 11:00:41
|
相似题推荐
解答题-问答题
|
适中
(0.65)
【推荐1】如图①,点 O 为直线
上一点,过点 O 作射线
,使
,将一直角三角板的直角顶点放在点 O 处,一边
在射线
上,另一边
在直线
的上方.
(1)在图①中,
度;
(2)将图①中的三角板绕点 O 按逆时针方向旋转,使得
在
的内部,如图②,若
,求
的度数;
(3)将图①中的三角板绕点 O 以每秒
的速度沿逆时针方向旋转一周,在旋转的过程中,当直线
恰好平分锐角
时,旋转的时间是 秒.(直接写出结果)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/828628c0876b45381c9a0edeb0fec236.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c36c0d4e38748fbb4a6cf5e700e5e874.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88e9f7d1272b7344346b58b660aa260a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b90e0f35eda1a729fed485f83da5ea9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aaf3369e0ea90e8d5cf4b6b3c45c0fd8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/6/14/aa9d1e0a-26de-4cd6-a7d5-e8295ab3e792.jpg?resizew=173)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/6/14/a5a1b16d-c863-4a83-9942-7f36db97b65d.jpg?resizew=177)
(1)在图①中,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/716e24f69149716b6224c19f0e47c5e6.png)
(2)将图①中的三角板绕点 O 按逆时针方向旋转,使得
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88e9f7d1272b7344346b58b660aa260a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d22df2977de56cc69be0c1e847653d7a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/601a0cdb308a5ce68367784bf36a15b4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b2f7bab4ed36ec5d04db3aeed2796f2.png)
(3)将图①中的三角板绕点 O 以每秒
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76c12e76fbd84eeec721386bd3b04cc4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88e9f7d1272b7344346b58b660aa260a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d22df2977de56cc69be0c1e847653d7a.png)
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解答题-问答题
|
适中
(0.65)
【推荐2】已知O是直线AB上的一点,∠COD是直角,OE平分∠BOC.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/9/23/08f1498f-3afd-48ba-80f9-a9147dc20b0a.png?resizew=431)
(1)如图①,若∠AOC=30°,求∠COE,∠DOB的度数.
(2)如图①,若∠AOC=α,求∠DOE的度数(用含α的代数式表示).
(3)将图①中的∠COD绕顶点O顺时针旋转至图②的位置,探究∠AOC与∠DOE的度数之间的数量关系,并说明理由.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/9/23/08f1498f-3afd-48ba-80f9-a9147dc20b0a.png?resizew=431)
(1)如图①,若∠AOC=30°,求∠COE,∠DOB的度数.
(2)如图①,若∠AOC=α,求∠DOE的度数(用含α的代数式表示).
(3)将图①中的∠COD绕顶点O顺时针旋转至图②的位置,探究∠AOC与∠DOE的度数之间的数量关系,并说明理由.
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解答题-问答题
|
适中
(0.65)
【推荐1】如图,∠CME+∠ABF=180°,MA平分∠CMN.若∠MNA=62°,求∠A的度数.根据提示将解题过程补充完整.
解:因为∠ABM+∠ABF=180°,
又因为∠CME+∠ABF=180°(已知),
所以∠ABM=∠CME
所以AB∥CD,理由:( )
所以∠CMN+( )=180°,
理由:(__________________________)
因为∠MNA=62°,
所以∠CMN=( )
因为MA平分∠CMN,
所以∠AMC=
∠CMN =( ).(角平分线的定义)
因为AB∥CD,
所以∠A=∠AMC=( )理由:(__________________________________)
解:因为∠ABM+∠ABF=180°,
又因为∠CME+∠ABF=180°(已知),
所以∠ABM=∠CME
所以AB∥CD,理由:( )
所以∠CMN+( )=180°,
理由:(__________________________)
因为∠MNA=62°,
所以∠CMN=( )
因为MA平分∠CMN,
所以∠AMC=
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
因为AB∥CD,
所以∠A=∠AMC=( )理由:(__________________________________)
![](https://img.xkw.com/dksih/QBM/2020/3/24/2426382182924288/2427216716103681/STEM/3ea147cde891468eba348fbfa3dea888.png?resizew=152)
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解答题-问答题
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适中
(0.65)
【推荐2】如图,直线AB与CD相交于点E,射线EG在∠AEC内(如图1).
![](https://img.xkw.com/dksih/QBM/2021/1/6/2630549846138880/2633304267350016/STEM/e001b746026b476f90551a01144e63d3.png?resizew=348)
(1)若∠BEC的补角是它的余角的3倍,则∠BEC= ________°;
(2)在(1)的条件下,若∠CEG比∠AEG小25度,求∠AEG的大小;
(3)如图2,若射线EF平分∠AED,∠FEG=m°(m>90°),则∠AEG﹣∠CEG=________°(用m的代表式表示).
![](https://img.xkw.com/dksih/QBM/2021/1/6/2630549846138880/2633304267350016/STEM/e001b746026b476f90551a01144e63d3.png?resizew=348)
(1)若∠BEC的补角是它的余角的3倍,则∠BEC= ________°;
(2)在(1)的条件下,若∠CEG比∠AEG小25度,求∠AEG的大小;
(3)如图2,若射线EF平分∠AED,∠FEG=m°(m>90°),则∠AEG﹣∠CEG=________°(用m的代表式表示).
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解答题-问答题
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适中
(0.65)
【推荐1】如图,直线AB,CD相交于点O,
,垂足为O,
,求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caea4e41982e2c5fe0a0c7e73af69c71.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81b28921c6d164765e03b47cfd6a734f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42e7b8a59f8d66176463f3d71f882a26.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/6/20/8b2a770b-5d9c-44a3-8855-c0623780a121.png?resizew=184)
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解答题-问答题
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适中
(0.65)
名校
【推荐2】如图,直线
与
交于点
,
,
平分
.
(1)若
,求
的度数;
(2)若
比
大
,求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a4a26b9ab8f36629aee288b6a0fc77c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6cad4595d5352b2884568a59d8d766a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42e7b8a59f8d66176463f3d71f882a26.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/28/c8fa598d-63ea-45cd-ad69-544cc9e62b33.png?resizew=168)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3c58a6b266aedbc37829b002617f569.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9fed1f57a835af4e9022e27603d12d31.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b2557547eecdc826b8282058802d217.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/418ebb89d29f4f631b055c911e8d178a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bab234099db50b451eb6ec2d5b21fe1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/843adec8fba1741ccb81a9017cfb815f.png)
您最近一年使用:0次