如图,直线
,
相交于点
,且
.若
,求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caea4e41982e2c5fe0a0c7e73af69c71.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73743882c492b8e68f3f99bc3751c35e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/418ebb89d29f4f631b055c911e8d178a.png)
更新时间:2024-04-22 16:41:44
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【推荐1】如图,点O在直线AB上,OC、OD是两条射线,OC⊥OD,射线OE平分∠BOC.
![](https://img.xkw.com/dksih/QBM/2020/2/25/2406431465054208/2406747515518976/STEM/83acb3373072433dac5bc59e53810bfa.png?resizew=152)
(1)若∠DOE=150°,求∠AOC的度数.
(2)若∠DOE=α,则∠AOC= .(请用含α的代数式表示)
![](https://img.xkw.com/dksih/QBM/2020/2/25/2406431465054208/2406747515518976/STEM/83acb3373072433dac5bc59e53810bfa.png?resizew=152)
(1)若∠DOE=150°,求∠AOC的度数.
(2)若∠DOE=α,则∠AOC= .(请用含α的代数式表示)
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【推荐2】如图,已知∠AOE是平角,OD平分∠COE,OB平分∠AOC,∠COD:∠BOC=2:3,求∠COD,∠BOC的度数.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/2/f41ea328-0863-4bd7-aa8d-6e6a52ad8e27.png?resizew=193)
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【推荐1】如图,已知AD⊥BC,EF⊥BC,垂足分别为D、F,∠2+∠3=180°,试说明:∠GDC=∠B.请补充说明过程,并在括号内填上相应的理由.
![](https://img.xkw.com/dksih/QBM/2021/5/19/2724406243196928/2781648966500352/STEM/bcfefa1c-d9f7-41bb-80a7-20f143f277b7.png?resizew=226)
解:∵AD⊥BC,EF⊥BC(已知)
∴∠ADB=∠EFB=90°
∴EF//AD( ),
∴∠1+∠2=180°( ).
又∵∠2+∠3=180°(已知),
∴∠1=∠3( ),
∴AB// ( ),
∴∠GDC=∠B( ).
![](https://img.xkw.com/dksih/QBM/2021/5/19/2724406243196928/2781648966500352/STEM/bcfefa1c-d9f7-41bb-80a7-20f143f277b7.png?resizew=226)
解:∵AD⊥BC,EF⊥BC(已知)
∴∠ADB=∠EFB=90°
∴EF//AD( ),
∴∠1+∠2=180°( ).
又∵∠2+∠3=180°(已知),
∴∠1=∠3( ),
∴AB// ( ),
∴∠GDC=∠B( ).
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【推荐1】如图,已知
,
平分
交
的延长线于点E,
平分
交
的延长线于点F,且与
交于点G,求证:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6dceb5cc71fc50f20649f6b9535fd914.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/85c4bdfb0db1e31e8459df1d15f9ab55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d39b8d91afc34e4a9b0fdbb6bafb9087.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6aa2b5e09f8ec785c59900a529390a02.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2947ca8e0cdbeb4aab80ce9e7b63ba98.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9e52a8f07834cbbbe4224962672fbbb2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/85c4bdfb0db1e31e8459df1d15f9ab55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06fb3a0dea2342716414d13c96f083a7.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/6/11/06e912cf-0be4-4362-946d-9c9bd5fe1559.png?resizew=151)
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【推荐2】如图,直线
相交于点
平分
,求:
(1)
的度数.
(2)
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5c4cd264c97c1f261229925cc5a6761.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5d8082441345bc5b4cdd342c09d977f8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3efb7dbe1173685b5a61ad263b93b7f8.png)
(1)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42e7b8a59f8d66176463f3d71f882a26.png)
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9fed1f57a835af4e9022e27603d12d31.png)
![](https://img.xkw.com/dksih/QBM/2021/2/18/2660689859133440/2669897675636736/STEM/2db8bfb1-9e89-451d-94ab-21b9e7992424.png)
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