名校
1 .
内角和我们可以这样理解:一根可自由伸缩的棍子(不考虑它的长度,棍子的一端有箭头),从状态1(与
重合)绕点A逆时针旋转大小为
的旋转量到状态2(与
重合),再绕点C逆时针旋转大小为
旋转量到状态3(与
重合),最后绕点B逆时针旋转大小为
的旋转量变为状态4,棍子回到了与
重合的状态,棍子逆时针转了半圈(棍子两端已互换),因此得到旋转量之和
.
![](https://img.xkw.com/dksih/QBM/2021/3/28/2687822354350080/2689861230362624/STEM/604ca13a95144bf3a15f06e0a3d4008a.png?resizew=309)
![](https://img.xkw.com/dksih/QBM/2021/3/28/2687822354350080/2689861230362624/STEM/2f535de3a4d94f46999fac57388b121a.png?resizew=218)
给出下列多边形中的8个角:
(如图标注),根据你对上述阅读材料的理解,请你建立这8个角的一个等量关系,则等式为___________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3818a2c9919d358b4c3713396093822b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/194741f4d2ae7ee44cafca780361446a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6b1bd1adfe4cc6566218f19970c2fd3b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/febc9a89d0d1c97b88c0f4acd32b4e67.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/791e819abbe4ecc6f2e7209839c4fc0b.png)
![](https://img.xkw.com/dksih/QBM/2021/3/28/2687822354350080/2689861230362624/STEM/604ca13a95144bf3a15f06e0a3d4008a.png?resizew=309)
![](https://img.xkw.com/dksih/QBM/2021/3/28/2687822354350080/2689861230362624/STEM/2f535de3a4d94f46999fac57388b121a.png?resizew=218)
给出下列多边形中的8个角:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a04583ebbcb5efceeb86df78ce956f3b.png)
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