1 . 如图,在四棱锥A-BCDE中,底面BCDE为矩形,M为CD中点,连接BM,CE交于点F,G为△ABE的重心.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/6/22/7224da7a-1027-4b1e-aefd-665541e1234b.png?resizew=178)
(1)证明:
平面ABC
(2)已知平面ABC⊥BCDE,平面ACD⊥平面BCDE,BC=3,CD=6,当平面GCE与平面ADE所成锐二面角为60°时,求G到平面ADE的距离.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/6/22/7224da7a-1027-4b1e-aefd-665541e1234b.png?resizew=178)
(1)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf60ad9db3411f35704fa88d86bfef5a.png)
(2)已知平面ABC⊥BCDE,平面ACD⊥平面BCDE,BC=3,CD=6,当平面GCE与平面ADE所成锐二面角为60°时,求G到平面ADE的距离.
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