如图,在矩形ABCD中,P是边AD上的动点,PE⊥AC于E,PF⊥BD于F,如果AB=3,AD=4,那么PE+PF=( )
![](https://img.xkw.com/dksih/QBM/2021/8/7/2780807660404736/2781827284779008/STEM/3535c87ff84347bebafbd355ba982f25.png?resizew=152)
![](https://img.xkw.com/dksih/QBM/2021/8/7/2780807660404736/2781827284779008/STEM/3535c87ff84347bebafbd355ba982f25.png?resizew=152)
A.![]() | B.3 | C.![]() | D.4 |
更新时间:2021-08-13 20:14:58
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【知识点】 根据矩形的性质与判定求线段长
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【推荐1】如图,在
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【推荐2】如图,在矩形ABCD中,AB=2,对角线AC与BD相交于点O,AE⊥BD,垂足为E.若BE=EO,则AD的长是( )
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