如图所示,在Rt△ABC中,AB=AC,D、E是斜边BC上的两点,且∠DAE=45°,△ADC≌△AFB,连接EF,有下列结论∶①BE=DC;②∠BAF=∠DAC; ③∠FAE=45°;④BF⊥BC.其中正确的有( )
![](https://img.xkw.com/dksih/QBM/2021/6/17/2744783966150656/2798854730743808/STEM/c93cfe29-412d-4288-9493-7d61b59d40a7.png)
![](https://img.xkw.com/dksih/QBM/2021/6/17/2744783966150656/2798854730743808/STEM/c93cfe29-412d-4288-9493-7d61b59d40a7.png)
A.①②③④ | B.②③ | C.②③④ | D.③④ |
20-21七年级下·广东深圳·期中 查看更多[2]
更新时间:2021-09-01 18:27:26
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