如图,矩形ABCD中,AD=2,AB=3,过点A,C作相距为2的平行线段AE,CF,分别交CD,AB于点E,F,则DE的长是( )
![](https://img.xkw.com/dksih/QBM/2016/7/18/1574220601540608/1574220607602688/STEM/32698bed494f4da790c3b634f584e495.png)
![](https://img.xkw.com/dksih/QBM/2016/7/18/1574220601540608/1574220607602688/STEM/32698bed494f4da790c3b634f584e495.png)
A.![]() | B.![]() | C.1 | D.![]() |
更新时间:2016-07-18 22:25:06
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【知识点】 相似三角形的判定与性质综合
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【推荐1】如图,AB是半圆O的直径,小宇按以下步骤作图:
(1)分别以A、B为圆心,大于AO长为半径作弧,两弧交于P点,连接OP与半圆交于C点;
(2)分别以A、C为圆心,大于
AC长为半径作弧,两弧交于Q点,连接OQ与半圆交于D点;
(3)连接AD、BD、BC,BD与OC交于E点.
根据以上作图过程及所作图形,下轮结论:①BD平分∠ABC;②BC∥OD;③CE=
OE.所有正确结论的序号是( )
![](https://img.xkw.com/dksih/QBM/2021/11/8/2847133274046464/2848131555557376/STEM/5628b2da-cc68-452e-b275-d68b7788d6ee.png?resizew=222)
(1)分别以A、B为圆心,大于AO长为半径作弧,两弧交于P点,连接OP与半圆交于C点;
(2)分别以A、C为圆心,大于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
(3)连接AD、BD、BC,BD与OC交于E点.
根据以上作图过程及所作图形,下轮结论:①BD平分∠ABC;②BC∥OD;③CE=
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf298f00799cbf34b4db26f5f63af92f.png)
![](https://img.xkw.com/dksih/QBM/2021/11/8/2847133274046464/2848131555557376/STEM/5628b2da-cc68-452e-b275-d68b7788d6ee.png?resizew=222)
A.①② | B.②③ | C.①③ | D.①②③ |
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【推荐2】如图,在平面直角坐标系中,直线
与
轴,
轴分别交于点
,点
,矩形
的顶点
分别在
轴,
轴上,对角线![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5e3c0430146b7b8d40ebb721a4d0de19.png)
轴,已知
,
.现将直线
向上平移
个单位长度,使平移后的直线恰好平分矩形
的面积,则
的值为( )
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/30/164ffbc8-0d53-4302-ba06-e4c6fd1f558a.png?resizew=200)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab57b0858dc6ea0665583ff5c86e994b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65436512ecbaefba4ac8123c55094211.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5e3c0430146b7b8d40ebb721a4d0de19.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/448c0a5ee776d19ce8e42ac9a5fd27c4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a1c6ba69264c8f203cd756581bc6280a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/30/164ffbc8-0d53-4302-ba06-e4c6fd1f558a.png?resizew=200)
A.![]() | B.8 | C.9 | D.![]() |
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