如图,AC是▱ABCD的对角线,在AD边上取一点F,连接BF交AC于点E,并
延长BF交CD的延长线于点G.
(1)若∠ABF=∠ACF,求证:CE2=EF•EG;
(2)若DG=DC,BE=6,求EF的长.
![](https://img.xkw.com/dksih/QBM/2019/1/31/2130423671824384/2131257584959488/STEM/890826463c554f26b4053f7147d149c2.png?resizew=5)
(1)若∠ABF=∠ACF,求证:CE2=EF•EG;
(2)若DG=DC,BE=6,求EF的长.
![](https://img.xkw.com/dksih/QBM/2019/1/31/2130423671824384/2131257584959488/STEM/6c2cb7b1d0e5476da8623154cf80f9b9.png?resizew=196)
更新时间:2019-01-13 09:30:57
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【知识点】 相似三角形的判定与性质综合
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解答题-证明题
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【推荐1】已知:如图,
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解答题-证明题
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名校
【推荐2】(1)如图1所示,
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