如图,在△AEF中,尺规作图如下:分别以点E、点F为圆心,大于
EF的长为半径作弧,两弧相交于G、H两点,作直线GH,交EF于点O,连接AO,则下列结论正确的是( )
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/19/4f88906d-e5d5-426c-bca9-9eda42681d2c.png?resizew=169)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/19/4f88906d-e5d5-426c-bca9-9eda42681d2c.png?resizew=169)
A.AO平分∠EAF | B.AO垂直EF | C.GH垂直平分EF | D.AO=OF |
更新时间:2019-05-23 08:45:38
|
【知识点】 线段垂直平分线的实际应用解读
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【推荐1】如图,在△ABC中,按以下步骤作图:①分别以A,B为圆心,大于
AB长为半径作弧,两弧相交于M,N两点;②作直线MN交BC于点D,连接AD.若AD=AC,∠B=25°,则∠C=( )
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A.70° | B.60° | C.50° | D.40° |
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【推荐2】如图,在平行四边形
中,利用直尺和圆规,分别以
、
为圆心,相同的长度为半径(半径大于线段
的一半)作四段弧,分别交于
、
两点,连接
、
,分别交
、
于
、
,连接
、
,则四边形
为( )
![](https://img.xkw.com/dksih/QBM/2020/5/7/2457465991258112/2457663644057600/STEM/1ffd223a-aaec-4304-8d7c-6be0f8301711.png)
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A.梯形 | B.平行四边形 | C.矩形 | D.菱形 |
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