如图,矩形ABCD中,AB
,BC
,连结对角线AC,点O为AC的中点,点E为线段BC上的一个动点,连结OE,将△AOE沿OE翻折得到△FOE,EF与AC交于点G,若△EOG的面积等于△ACE的面积的
,则BE=_____ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bbb626b5b260e30e0262785514c62d3d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3e2eb5b627e65b16a60cf76b84410c5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10402e4ddd0d323cc1ae83801ae976db.png)
![](https://img.xkw.com/dksih/QBM/2019/6/23/2231947036106752/2232385659396097/STEM/5034a7da790b440a97b4d91709981837.png?resizew=155)
更新时间:2019-06-24 10:23:09
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【知识点】 根据矩形的性质求面积解读
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【推荐1】已知如图,矩形ABCD中AB=4cm,BC=3cm,点P是AB上除A,B外任一点,对角线AC,BD相交于点O,DP,CP分别交AC,BD于点E,F,且
ADE和三角形BCF的面积之和4cm2,则四边形PEOF的面积为___ .
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【推荐2】如图,现将四根木条钉成的矩形框
变形为平行四边形木框
,且
与
相交于
边的中点E,若
,
,则原矩形
和平行四边形
重叠部分的面积是 __ .
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