1 . 人们很早以前就开始探索高次方程的数值求解问题.牛顿在《流数法》一书中给出了牛顿迭代法:用“作切线”的方法求方程的近似解.具体步骤如下:设
是函数
的一个零点,任意选取
作为
的初始近似值,曲线
在点
处的切线为
,设
与
轴交点的横坐标为
,并称
为
的1次近似值;曲线
在点
处的切线为
,设
与
轴交点的横坐标为
,称
为
的2次近似值.一般地,曲线
在点
处的切线为
,记
与
轴交点的横坐标为
,并称
为
的
次近似值.在一定精确度下,用四舍五入法取值,当
与
的近似值相等时,该近似值即作为函数
的一个零点
的近似值.下列说法正确的是( )
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A.![]() |
B.利用牛顿迭代法求函数![]() ![]() ![]() ![]() |
C.利用二分法求函数![]() ![]() ![]() ![]() |
D.利用牛顿迭代法求函数![]() ![]() ![]() ![]() |
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