已知∠AOB=120°,点P为射线OA上一动点(不与点O重合),点C为∠AOB内部一点,连接CP,将线段CP绕点C顺时针旋转60°得到线段CQ,且点Q恰好落在射线OB上,不与点O重合.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/2/28/4b977df2-bddd-43c6-b115-89bd9291bde0.png?resizew=381)
(1)依据题意补全图1;
(2)用等式表示∠CPO与∠CQO的数量关系,并证明;
(3)连接OC,写出一个OC的值,使得对于任意点P,总有OP+OQ=4,并证明.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/2/28/4b977df2-bddd-43c6-b115-89bd9291bde0.png?resizew=381)
(1)依据题意补全图1;
(2)用等式表示∠CPO与∠CQO的数量关系,并证明;
(3)连接OC,写出一个OC的值,使得对于任意点P,总有OP+OQ=4,并证明.
2020·北京丰台·一模 查看更多[1]
更新时间:2020-06-02 11:16:19
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