如图,Rt△ABC中,∠C=90°,利用尺规作图在BC,BA上分别截取BE,BD,使BE=BD;分别以D,E为圆心、以大于
DE的长为半径作弧,两弧在∠CBA内交于点F;作射线BF交AC于点G.若CG=2,则点G到直线AB的距离为( )
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/20/390ddd86-4f40-4fc1-acf0-30dd3b27412b.png?resizew=148)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/20/390ddd86-4f40-4fc1-acf0-30dd3b27412b.png?resizew=148)
A.1 | B.2 | C.3 | D.4 |
20-21八年级下·贵州铜仁·期末 查看更多[2]
更新时间:2021-08-13 19:47:23
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【推荐1】如图,AD是
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【推荐2】如图,
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【推荐1】如图,在
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【推荐2】如图,在Rt△ABC中,∠C=90°,AC=BC,按以下步骤作图:①以点A为圆心,以任意长为半径作弧,分别交AC,AB于点M,N;②分别以M,N为圆心,以大于
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![](https://img.xkw.com/dksih/QBM/2022/5/30/2990505034948608/2991072127033344/STEM/813ef509-a343-4846-a620-d8b7b8521718.png?resizew=241)
A.6 | B.![]() | C.![]() | D.![]() |
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