已知,在△ABC中,AC=BC,BE⊥CE,垂足分别为D,E
![](https://img.xkw.com/dksih/QBM/2022/7/11/3020371721617408/3020549965127680/STEM/7a9bfce94d8a49cea72d0f28bb73417c.png?resizew=473)
(1)求证:∠ACB=90°;
(2)点O为AB的中点,连接OD,OE.请判断△ODE的形状?并说明理由.
![](https://img.xkw.com/dksih/QBM/2022/7/11/3020371721617408/3020549965127680/STEM/7a9bfce94d8a49cea72d0f28bb73417c.png?resizew=473)
(1)求证:∠ACB=90°;
(2)点O为AB的中点,连接OD,OE.请判断△ODE的形状?并说明理由.
更新时间:2022-07-11 23:47:32
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【推荐1】在平面直角坐标系中,直线AB与x轴交于点A,与y轴交于点B,与直线OC:y1=x交于点C.
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(1)当直线AB解析式为y2=﹣
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(2)如图2,作∠AOC的平分线ON,若AB⊥ON,垂足为E,
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【推荐2】如图,点A,P,B,C是⊙O上的四个点,∠DAP=∠PBA.
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(2)若∠APC=∠BPC=60°,试探究线段PA,PB,PC之间的数量关系,并证明你的结论;
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【推荐1】已知,如图,
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【推荐2】如图,BC为⊙O直径,点A是⊙O上任意一点(不与点B、C重合),以BC、AB为邻边的平行四边形ABCD的顶点D在⊙O外.
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