如图,AD是△ABC的角平分线,作AD的垂直平分线EF交BC的延长线于点F,连接AF.给出下列结论:
①AF=DF;
②S△ABD:S△ACD=AB:AC;
③∠BAF=∠ACF.
其中正确的结论为( )
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/16/2d700541-277a-46b8-a93c-e75452d8906c.png?resizew=164)
①AF=DF;
②S△ABD:S△ACD=AB:AC;
③∠BAF=∠ACF.
其中正确的结论为( )
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/16/2d700541-277a-46b8-a93c-e75452d8906c.png?resizew=164)
A.①③ | B.①② | C.①②③ | D.②③ |
更新时间:2022-08-18 14:01:49
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