如图,在平行四边形
中,以点A为圆心,
长为半径画弧交
于点F,再分别以点B、F为圆心,大于
长为半径画弧,两弧交于点P连接
并延长交
于E,连接
,得到四边形
.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/1/cf89c269-7389-4df1-93f5-fef019fe4a29.png?resizew=259)
(1)根据以上尺规作图的过程,判断四边形
的形状并证明;
(2)若
,求菱形
的周长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/40fe477aea662f3ae9b6d28f1e785147.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20a541b81584a032f571159ea152c85a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2dde327febef2331a4766a79b433cc02.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/1/cf89c269-7389-4df1-93f5-fef019fe4a29.png?resizew=259)
(1)根据以上尺规作图的过程,判断四边形
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2dde327febef2331a4766a79b433cc02.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3bae399b4c402f54037040c14858dcd3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2dde327febef2331a4766a79b433cc02.png)
更新时间:2022-09-24 10:41:20
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【推荐2】如图,四边形ABCD是平行四边形,AE⊥BC,AF⊥CD,垂足分别为E,F,且BE=DF.
(2)连接EF并延长,交AD的延长线于点G,若∠CEG=30°,AE =2,求EG的长.
(2)连接EF并延长,交AD的延长线于点G,若∠CEG=30°,AE =2,求EG的长.
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真题
【推荐1】阅读理解:
如图①,如果四边形ABCD满足AB=AD,CB=CD,∠B=∠D=90°,那么我们把这样的四边形叫做“完美筝形”.
将一张如图①所示的“完美筝形”纸片ABCD先折叠成如图②所示形状,再展开得到图③,其中CE,CF为折痕,∠BCE=∠ECF=∠FCD,点B′为点B的对应点,点D′为点D的对应点,连接EB′,FD′相交于点O.
![](https://img.xkw.com/dksih/QBM/2015/8/5/1573891986006016/1573891991871488/STEM/b6313ba70bc64170acd7feee2e0dabf4.png)
简单应用:
(1)在平行四边形、矩形、菱形、正方形四种图形中,一定为“完美筝形”的是 ;
(2)当图③中的∠BCD=120°时,∠AEB′= °;
(3)当图②中的四边形AECF为菱形时,对应图③中的“完美筝形”有 个(包含四边形ABCD).
拓展提升:
(4)当图③中的∠BCD=90°时,连接AB′,请探求∠AB′E的度数,并说明理由.
如图①,如果四边形ABCD满足AB=AD,CB=CD,∠B=∠D=90°,那么我们把这样的四边形叫做“完美筝形”.
将一张如图①所示的“完美筝形”纸片ABCD先折叠成如图②所示形状,再展开得到图③,其中CE,CF为折痕,∠BCE=∠ECF=∠FCD,点B′为点B的对应点,点D′为点D的对应点,连接EB′,FD′相交于点O.
![](https://img.xkw.com/dksih/QBM/2015/8/5/1573891986006016/1573891991871488/STEM/b6313ba70bc64170acd7feee2e0dabf4.png)
简单应用:
(1)在平行四边形、矩形、菱形、正方形四种图形中,一定为“完美筝形”的是 ;
(2)当图③中的∠BCD=120°时,∠AEB′= °;
(3)当图②中的四边形AECF为菱形时,对应图③中的“完美筝形”有 个(包含四边形ABCD).
拓展提升:
(4)当图③中的∠BCD=90°时,连接AB′,请探求∠AB′E的度数,并说明理由.
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【推荐2】如图,在等腰
中,
,点D是
中点,
交
于点E,
交
于点F,且
.
是菱形;
(2)求四边形
的面积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/047dc9795efa99b6fb9fdf9778085dab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/105068b25f5a63af32f4082cfe08691e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/100b3e7dcd5f34c5234971cd75bff138.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e446693eb568c1df291b9fee435e53c1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48a61d8bedef61745ee4fd89a8c0c119.png)
(2)求四边形
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48a61d8bedef61745ee4fd89a8c0c119.png)
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【推荐1】如图,在平行四边形
中,
,
,
.若点E从点B出发以每秒1个单位长度的速度沿B—C—D向终点D运动,运动时间为t秒.过点E作点E所在的边(当点E与C重合时,点E所在边为
)的垂线,交四边形
其他的边于点F,在
的右侧作正方形
.
的长;
(2)当
时,求证:四边形
为平行四边形;
(3)当点E在边
上,且正方形
有且只有两个顶点位于四边形
的边上时,求t的取值范围;
(4)当四边形
为平行四边形时,直接写出
的长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c6b0f0cdb98fe345dccfa96b3be72b31.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/080ca48cd27d4bf9d9ef084b558fc17a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c42ed2e5bd5a0f033e24008697bf4963.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b3354914d3a733d1483ce86567f9320a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
(2)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8cbeede118c407a800b05757b9a1393e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88835e8296ae97961cc3fe3426bc7326.png)
(3)当点E在边
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b3354914d3a733d1483ce86567f9320a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
(4)当四边形
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/910936ec9fb419d51ce2f5ea817f8401.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/77a7e4a6765ce78b05ee97764771e01f.png)
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【推荐2】如图,在△ABC中,∠ABC=90°,BD为AC的中线,过点C作CE⊥BD于点E,过点A作BD的平行线,交CE的延长线于点F,在AF的延长线上截取FG=BD,连接BG、DF.
(1)求证:四边形BDFG为菱形;
(2)若AG=13,CF=6,求四边形BDFG的周长.
(1)求证:四边形BDFG为菱形;
(2)若AG=13,CF=6,求四边形BDFG的周长.
![](https://img.xkw.com/dksih/QBM/2020/2/28/2408569639534592/2408877728284672/STEM/3047fdcd2b0e4dce9da05b919dc1a648.png?resizew=237)
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【推荐1】如图,在
中,
,
是
的角平分线,点
是
的中点.过点
作
,作射线
交
于点
,连结
.
是矩形.
(2)若
,
,直接写出矩形
的面积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/047dc9795efa99b6fb9fdf9778085dab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de13b90ee61450dcf26f2f04b010b3b4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/77a7e4a6765ce78b05ee97764771e01f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cae70b8a9d2d2e96dea62c00ced04b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/94a5a2949b3d520ed03d57126c7d4d8d.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b939af5ba06e279cce39396aaf0fae06.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/185522e1d984c23e8803da956eed803f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/94a5a2949b3d520ed03d57126c7d4d8d.png)
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【推荐2】如图,一次函数
与反比例函数
的图象交于
、
两点,点
坐标为
,点
坐标为
,直线
交
轴于点
,过
作
轴的垂线,交反比例函数图象于点
,连接
、
,
与
轴正半轴夹角的正切值为
.
![](https://img.xkw.com/dksih/QBM/2018/9/15/2033131982053376/2034084890574849/STEM/1bf8c3d7b1314256adac09996a9a16bc.png?resizew=141)
求一次函数与反比例函数的解析式;
求
的面积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b5324645d81b339fa25ccb2951f77e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f81678dc6553c3121da130e81be7a18.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c48ea1a24a8c17ed02c3461a40383cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5c9c6f428ecf50461b54b1bd261543e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c042ff18466e8165fadf343d142a4b0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b3182db896bc2462331796e2a6108363.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb84f6fbac102ccf326b2223d69cb7cc.png)
![](https://img.xkw.com/dksih/QBM/2018/9/15/2033131982053376/2034084890574849/STEM/1bf8c3d7b1314256adac09996a9a16bc.png?resizew=141)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4141b26d2c32655003494a91ad6331b5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65863c1abad833b79c303bfca24f535c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c65975206b84eba998df39052348174a.png)
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