判断下列命题是否正确,并说明理由.
(1)对角互补的平行四边形是矩形.
(2)一组邻角相等的平行四边形是矩形.
(3)对角线相等的四边形是矩形.
(4)内角都相等的四边形是矩形.
(1)对角互补的平行四边形是矩形.
(2)一组邻角相等的平行四边形是矩形.
(3)对角线相等的四边形是矩形.
(4)内角都相等的四边形是矩形.
21-22八年级下·全国·课后作业 查看更多[1]
(已下线)【浙教版课时练习】八年级下册5.1 矩形
更新时间:2022-11-28 20:59:39
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【推荐1】如图,在平行四边形
中,
分别是
,
的角平分线.求证:四边形
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
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【推荐2】已知:如图,四边形ABCD为平行四边形,点E、A、C、F在同一直线上,
.求证:
(1)![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f8f7a3cf5a6acc41c4932eb8548e9e7.png)
(2)![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf1e9308749258afdae2adfc06ce061f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d8ce1475f537b4ad21775bfaa16daa0c.png)
(1)
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(2)
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【推荐1】如图,在
中,
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的平分线
交
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5138a9f70d5e8b0580e30fef6eb7baef.png)
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【推荐2】如图,在
ABC中,AB=AC,在BC上任取一点D,以AB、BD为邻边构造平行四边形ABDE,连接CE.
(1)求证:
ABD≌
CAE;
(2)当点D在边BC的什么位置时,四边形ADCE是矩形?证明你的结论.
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(1)求证:
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(2)当点D在边BC的什么位置时,四边形ADCE是矩形?证明你的结论.
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