如果无理数m的值介于两个连续正整数之间,即满足
(其中a、b为连续正整数),我们则称无理数m的“神奇区间”为
.例:
,所以
的“神奇区间”为
.若某一无理数的“神奇区间”为
,且满足
,其中
,
是关于x、y的二元一次方程组
的一组正整数解,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df5be1440d099f464ef46dee39de6010.png)
__ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/becb9999878ace1f53138c1ce0cb18d4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/472630cb9d24294eb39f2a08a63b3537.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caedd970d24def67811a2d9192b6fa52.png)
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22-23八年级上·四川内江·期中 查看更多[8]
四川省内江市市中区内江市第六中学2022-2023学年八年级上学期期中数学试题(已下线)期中押题重难点检测卷(拔尖卷)(考试范围:第1-3章)-【帮课堂】2022-2023学年八年级数学下册同步精品讲义(浙教版)(已下线)期末押题预测(培优压轴卷)-【微专题】2022-2023学年八年级数学下册常考点微专题提分精练(苏科版)(已下线)压轴真题必刷01 实数和勾股定理(压轴30题5种题型训练)-2023-2024学年八年级数学上学期期末考点大串讲(北师大版)01-实数(已下线)专题16.20 二次根式(分层练习)(培优练)-2023-2024学年八年级数学下册基础知识专项突破讲与练(人教版)(已下线)专题12.13 二次根式(全章分层练习)(培优练)-2023-2024学年八年级数学下册基础知识专项突破讲与练(苏科版)(已下线)2023—2024学年名校期末好题汇编(人教版八年级数学下册)——专题一—二次根式
更新时间:2022-12-28 19:39:29
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【推荐1】已知点
,其中
,
,
,且
、
、
、
均为整数,那么在平面直角坐标系中点
的可能位置共有__________ 个.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d065940ce3778d81cb388736d13b25d3.png)
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【推荐2】归纳并猜想:
(1)
的整数部分为____ ;
(2)
的整数部分为____ ;
(3)
的整数部分为____ ;
(4)猜想:当n为正整数时,
的整数部分为____ ,并把小数部分表示出来为____ .
(1)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/af09066970c5b676e38185230a1a3f18.png)
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15482e9cce4aee75f52d6e16ca25d75c.png)
(3)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a4321e4ecc909aa1f208712ce4e0c423.png)
(4)猜想:当n为正整数时,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a459aa17114221d3b233267545175c06.png)
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【推荐1】如果一个四位自然数M各数位上的数字均不为0,将M的千位和个位上的数字对调,同时将M的百位和十位上的数字对调,得到新的四位数N,称N为M的“一对称数”,并规定
.例如:3412的“对称数”为2143,
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab4f2ef3ab35aeb98433de27b1f168e7.png)
______ ;若
(m为整数,
),
(n为整数,
),且
,s和t的各数位数字均不为0,且s的“对称数”与t的“对称数”之和能被9整除,规定
,则k最大值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e9b0e2e46bf5c88f2587eafdcf468877.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/78f5acfe8d824dec54f9ba14aa099854.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab4f2ef3ab35aeb98433de27b1f168e7.png)
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【推荐2】对于一个四位正整数
,若它的千位数字与十位数字之和等于百位数字与个位数字之和,则称这个四位正整数
是“和谐数”.如:四位数2783,
,
是“和谐数”;四位数5326,
,
不是“和谐数”,则最小的“和谐数”是______ ;若一个“和谐数”
满足千位数字与百位数字的平方差是24,且十位数字与个位数字的和能被5整除,则满足条件的
的最大值是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
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【推荐3】一个四位数
的各个数位上的数字均不为0,且满足位十数字是千位数字的2倍,个位数字比百位数字大2.则称这个四位数
为“和2倍数”.例如:
,因为
,
,所以2143为“和2倍数”.已知
为“和2倍数”,若将
的各个数位上的数字重新拆分组合成2个新的两位数,其中
的千位与十位数字分别作为2个两位数的十位,
的百位与个位数字分别为作为2个两位数的个位,把按照这种方式组成的所有两位数的和记为
.①当
,则
__________ ;②当
能被7整除时,则满足条件的
的最小值为__________ .
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【推荐1】将一组数
,2,
,2
,
,…,2
按图中的方法排列:
![](https://img.xkw.com/dksih/QBM/2017/11/18/1819689246523392/1820127040626689/STEM/229689702a344a9e93d7697d920439c9.png?resizew=335)
若3
的位置记为(2,3),2
的位置记为(3,2),则这组数中最大数的位置记为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf298f00799cbf34b4db26f5f63af92f.png)
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![](https://img.xkw.com/dksih/QBM/2017/11/18/1819689246523392/1820127040626689/STEM/229689702a344a9e93d7697d920439c9.png?resizew=335)
若3
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf298f00799cbf34b4db26f5f63af92f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/619096595112f0340a43b756e114dd3d.png)
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【推荐2】已知
(
均为实数),则
的最大值与最小值之差为______ .
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【推荐2】某食品店推出两款袋装营养早餐配料,甲种每袋装有10克花生,10克芝麻,10克核桃;乙种每袋装有20克花生,5克芝麻,5克核桃.甲、乙两款袋装营养早餐配料每袋成本价分别为袋中花生、芝麻、核桃的成本价之和.已知花生每克成本价0.02元,甲款营养早餐配料的售价为2.6元,利润率为30%,乙款营养早餐配料每袋利润率为20%.若这两款袋装营养早餐配料的销售利润率达到24%,则该公司销售甲、乙两款袋装营养早餐配料的数量之比是______ .
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