如图,Rt△ABC中,∠ACB=90°,∠BAC与∠CBE的平分线相交于点P,BE=BC,PB与CE交于点H,PG∥AD交BC于F,交AB于G,下列结论:①GA=GP;②∠DCP=45°;③BP垂直平分CE;④GF+ FC =GA;其中正确的判断有______________ .(填序号)
![](https://img.xkw.com/dksih/QBM/2018/1/17/1862156692938752/1863179241095168/STEM/a3e2145231c84033a7ad10e2a9ded2e3.png?resizew=189)
更新时间:2018-01-18 11:10:46
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