在矩形ABCD中,E为CD的中点,H为BE上的一点,,连接CH并延长交AB于点G,连接GE并延长交AD的延长线于点F.
(1)求证: AB·BH=2BG·EH
(2)若∠CGF=90°,
=3时,求
的值.
(1)求证: AB·BH=2BG·EH
(2)若∠CGF=90°,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/45f0b77ac4fd16f339fabab62351e8e1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2465ee1fec12351943f15055dfd6ec73.png)
![](https://img.xkw.com/dksih/QBM/2018/5/18/1948050121121792/1950159606218752/STEM/d3419da737ae47e1b90f80086e9c63cd.png?resizew=231)
更新时间:2018-05-21 16:32:47
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解答题-证明题
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【推荐2】如图1,矩形
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解答题-证明题
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【推荐1】已知:如图,在△ABC中,点D、E分别在边AB、AC上,DE∥BC,点F在边AB上,BC2=BF•BA,CF与DE相交于点G.
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解答题-作图题
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【推荐2】如图,小涵和小西想要测量建筑物OP与广告牌AB的高度.首先,小涵站在D处看到广告牌AB的顶端A、建筑物OP的顶端O在一条直线上;然后,在阳光下,小西站在N处,此时他的影长为NE,同一时刻,测得建筑物OP的影长为PG,OP⊥PD,AB⊥PD,CD⊥PD,MN⊥PD.
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②求出广告牌AB的高度.
![](https://img.xkw.com/dksih/QBM/2019/11/29/2344412399951872/2345736076320768/STEM/ebd9eed255864d41aa39c5fca3f5c816.png?resizew=229)
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