如图,在⊙O中,点P为直径BA延长线上一点,PD切⊙O于点D、过点B作BH⊥PH,点H为垂足,BH交⊙O于点C,连接BD,CD.
(1)求证:BD平分∠ABH;
(2)若CD=2,∠ABD=30°,求⊙O的直径的长.
(1)求证:BD平分∠ABH;
(2)若CD=2,∠ABD=30°,求⊙O的直径的长.
![](https://img.xkw.com/dksih/QBM/2018/11/17/2077590067519488/2078282685079552/STEM/4f86c1c4b4994c288767453da025c0f3.png?resizew=217)
更新时间:2018-11-17 19:57:02
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解答题-证明题
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【推荐1】【问题背景】如图1,
,
均为等边三角形.求证:
;
【解决问题】
为等边三角形,点D在边AB上,点E是边AC上一个动点(不与点A,点C重合),以DE为边作等边
.
①如图2,若点D与点B重合,点G在BA延长线上,且
.试探索线段CF,AG,AB之间有何数量关系?并证明你的结论;
②如图3,若
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【解决问题】
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①如图2,若点D与点B重合,点G在BA延长线上,且
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c2e2cb8956c9e4695f506e9d0b3e1292.png)
②如图3,若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
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解答题-证明题
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【推荐2】菱形ABCD中,∠B=60°,E,F分别为边BC,CD上的点,且BE=CF.求证S四边形AECF=
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解答题-证明题
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【推荐1】如图,在Rt△ABC中,∠ACB=90°,以AC为直径的⊙O与AB边交于点D,过点D作⊙O的切线,交BC于点E.
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(1)求证:点E是边BC的中点;
(2)若EC=3,BD=
,求⊙O的直径AC的长度;
(3)若以点O,D,E,C为顶点的四边形是正方形,试判断△ABC的形状,并说明理由.
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(1)求证:点E是边BC的中点;
(2)若EC=3,BD=
![](https://img.xkw.com/dksih/QBM/2011/12/16/1573308050669568/1573308124839936/STEM/7685e16a02b8448ea698d881a2960cec.png?resizew=29)
(3)若以点O,D,E,C为顶点的四边形是正方形,试判断△ABC的形状,并说明理由.
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解答题-证明题
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【推荐2】如图,在
中,
,
是
的平分线,
是
上一点,以
为半径的
经过点
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![](https://img.xkw.com/dksih/QBM/2018/9/15/2033146566975488/2034102237372416/STEM/e56b46e30ae54141b76f8a90716cc63e.png?resizew=114)
求证:
是
切线;
若
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