1 . 命题:“∀x>0,都有x2﹣x≥0”的否定是
A.∀x≤0,都有x2﹣x>0 | B.∀x>0,都有x2﹣x≤0 |
C.∃x>0,使得x2﹣x<0 | D.∃x≤0,使得x2﹣x>0 |
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A.∀x≤0,都有x2﹣x>0 | B.∀x>0,都有x2﹣x≤0 |
C.∃x>0,使得x2﹣x<0 | D.∃x≤0,使得x2﹣x>0 |