1 . 二进制数是用0和1表示的数,它的基数为2,进位规则是“逢二进一”,借位规则是“借一当二”,二进制数
(
)对应的十进制数记为
,即
其中
,
,则在
中恰好有2个0的所有二进制数
对应的十进制数的总和为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7dc67c44ee56d212e321d009647ab945.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19248c4252fabfaf0d55c96985d79989.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bc9369d6e6f9022be0f24b7e0c7f86d3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5f9357d4176e0bb37e26897e7946b528.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/05250abe6da85eb0b555948d7dbaf317.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/489340c9a2d70c00bae13b7018cad448.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/99e15a976f0109e308a61012431d9778.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/748c4f2d1653f946a5f81024643881ee.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/47042681f994e3432bc00024d1631bf8.png)
A.1910 | B.1990 | C.12252 | D.12523 |
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2 . 已知二进制和十进制可以相互转化,例如
,则十进制数89转化为二进制数为
.将
对应的二进制数中0的个数,记为
(例如:
,
,
,则
,
,
),记
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a264948c768a250404d1cbbbfffc433.png)
__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/048e0e93e4f2c324160c032a96a8c2be.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/084c0570dc21c7107ce53309533cf95e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/96abfe2da27a63e6affb19a0c80236d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/440a7c6e674e9736936b3a81aec830c1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6496481fec463fdf799c29347b37f83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e5e8702525913045c7ced4ce46d697f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1d77060931748cee8c21b43d15033b22.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20509cff32749ebc22bb2640959ac6d4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/521f0256a6cfba8ae4a2d0b9b3d4adec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d362d1f0a28b5aac138d019cec83fe91.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a264948c768a250404d1cbbbfffc433.png)
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(已下线)重难点:二项式定理(提高卷)-【同步题型讲义】2022-2023学年高二数学同步教学题型讲义(人教A版2019选择性必修第三册)河南省郑州第一中学2019届高三第二次联合质量测评理科数学试题(已下线)专题33 二项式定理-冲刺2020高考跳出题海之高三数学模拟试题精中选萃(已下线)专题8.3 临界知识问题 玩转压轴题-玩转压轴题,进军满分之2021高考数学选择题填空题