名校
1 . 已知
是第二象限角,且
,
是第一象限角,且![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fbe2212c10c3da621f550e8c6409bd7.png)
(1)求
,
;
(2)若对于任意的角
都有
成立,求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a92b5f617460604b942a9c302b3a41ff.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fbe2212c10c3da621f550e8c6409bd7.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b4179e1ab8705cf19ea7aaf48888843.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3eacde1c42151734fdc60f3001b590de.png)
(2)若对于任意的角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80ada15d54503b8770cdf8d73f7bb2d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2f372b43f190f84b3bbdf423102fd624.png)
您最近一年使用:0次
名校
解题方法
2 . 古希腊数学家阿波罗尼斯采用平面切割圆锥面的方法来研究圆锥曲线,如图1,设圆锥轴截面的顶角为
,用一个平面
去截该圆锥面,随着圆锥的轴和
所成角
的变化,截得的曲线的形状也不同.据研究,曲线的离心率为
,比如,当
时,
,此时截得的曲线是抛物线.如图2,在底面半径为
,高为
的圆锥
中,
、
是底面圆
上互相垂直的直径,
是母线
上一点,
,平面
截该圆锥面所得的曲线的离心率为( )
![](https://img.xkw.com/dksih/QBM/editorImg/2023/5/9/011f64b8-0f83-457b-8f87-5174f47d8bce.png?resizew=143)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/5/8/1441e670-fcd8-48fb-a66c-daa471c37e98.png?resizew=176)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8dd0c52aca1675c17b9a019aa7901e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4bcd8ee2d8367c167d6ae0abc741b6b8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4bcd8ee2d8367c167d6ae0abc741b6b8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0e55f4e5a5d84670bbf3de150da74b62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ffa3205b1df826d63914dcb55bb3ab43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09dbcaa127022fbd6b6f13345196408a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2967337e3fcb228dded64ab0c41a17e0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c2bc5e50b8dfa02601c70822252854a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3358e5017bb8701143245ad5a1568219.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c09afc70f448545336304333d5b5658b.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/5/9/011f64b8-0f83-457b-8f87-5174f47d8bce.png?resizew=143)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/5/8/1441e670-fcd8-48fb-a66c-daa471c37e98.png?resizew=176)
A.![]() | B.![]() | C.![]() | D.![]() |
您最近一年使用:0次
2023-05-06更新
|
1078次组卷
|
5卷引用:贵州省贵阳市2023届高三适应性考试(二)数学(理)试题