如图所示,圆柱体固定在地面上,表面光滑,轻质橡皮绳一端连接小球甲,另一端跨过圆柱体连接小球乙,乙通过细绳与地面连接,甲质量是乙的2倍,甲乙均静止。将连接地面的细绳剪断瞬间( )
A.甲球的加速度为g |
B.甲球处于处于失重状态 |
C.乙球处于处于超重状态 |
D.乙球处于平衡状态 |
更新时间:2021-11-17 10:32:56
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【知识点】 牛顿第二定律求瞬时突变问题
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【推荐1】如图甲,乙所示,物块
、
、
、
的质量均为m,
、
用刚性轻杆连接,
、
用轻质弹簧连接,两个装置都放在水平的支托物上,处于平衡状态。今突然撤去支托物,让物块下落,在撤去支托物的瞬间,
、
受到的合力分别为
、
,
、
受到的合力分别为
、
,不计空气阻力。则( )
![](https://img.xkw.com/dksih/QBM/2020/3/16/2421008528433152/2422213135040512/STEM/203ce159-e7e4-46bc-80c1-9eb0dae4558d.png?resizew=227)
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【推荐2】如图所示,斜面上用一细绳连接箱体C,有A、B两小球用轻质弹簧相连、放置于箱体内处于平衡.已知
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