等腰△ABC中,AB=AC,∠ACB=72°,
(1)如图1,若BD⊥AC于D,求∠ABD的度数;
(2)如图2,若CE平分∠ACB,求证:AE=BC.
(1)如图1,若BD⊥AC于D,求∠ABD的度数;
(2)如图2,若CE平分∠ACB,求证:AE=BC.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/6/29/03ee4557-430b-45ec-a2bf-836c9651db10.png?resizew=235)
19-20八年级上·江苏盐城·期中 查看更多[2]
更新时间:2020-10-29 10:51:56
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【推荐2】如图,已知点D为等腰直角三角形ABC内一点,AC=BC,∠ACB=90°,∠CAD=∠CBD=15°,E为AD的延长线上的一点,且CE=CA.
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