如图,在Rt△ACB1中,∠C=90°,AC=B1C=1.以AB1为直角边作Rt△AB1B2,使∠AB1B2=90°,B1B2=1;再以AB2为直角边作Rt△AB2B3,使∠AB2B3=90°,B2B3=1;------,依此规律做下去,可以得到Rt△AB7B8,且∠AB7B8=90°,B7B8=1,此时边AB8的长是_____ .
![](https://img.xkw.com/dksih/QBM/2020/11/2/2584382257160192/2589478787530752/STEM/e85b7add77f84a0881c5865aefc06b21.png?resizew=184)
更新时间:2020-11-09 22:50:59
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