如图,在Rt△ABC中,∠C=90°,∠ABC的平分线BD交AC于点D,DE⊥DB交AB于点E,设⊙O是△BDE的外接圆.
![](https://img.xkw.com/dksih/QBM/2022/3/18/2938718166687744/2957257776652288/STEM/83fb4f6e-9555-4f59-b073-892ae8982bc1.png?resizew=120)
(1)求证:AC是⊙O的切线;
(2)求证:△ADE∽△ABD;
(3)若DE=2,BD=4,求AE的长.
![](https://img.xkw.com/dksih/QBM/2022/3/18/2938718166687744/2957257776652288/STEM/83fb4f6e-9555-4f59-b073-892ae8982bc1.png?resizew=120)
(1)求证:AC是⊙O的切线;
(2)求证:△ADE∽△ABD;
(3)若DE=2,BD=4,求AE的长.
更新时间:2022-04-13 13:39:15
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解答题-证明题
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适中
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名校
【推荐1】如图,在
中,
是边
的垂直平分线,且
,延长
,
交于点F,连接
.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/17/a6923bcd-1331-4007-b6cc-5459e052863b.png?resizew=182)
(1)求证:
;
(2)若
,
,求
的长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
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![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/17/a6923bcd-1331-4007-b6cc-5459e052863b.png?resizew=182)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed10df4140819d5451773a45de66201b.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd0763b031b7e6b6d87ce3554ac482d5.png)
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解答题-证明题
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适中
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解题方法
【推荐2】在
中,
,将
绕点A顺时针旋转到
的位置,点E在斜边AB上,连结BD,过点D作
于点F.
(1)如图1,若点F与点A重合.①求证:
;②若
,求出
;
(2)若
,如图2,当点F在线段CA的延长线上时,判断线段AF与线段AB的数量关系.并说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aefc12c61c95d8e36846a6aac1c9105b.png)
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(1)如图1,若点F与点A重合.①求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b10134e7a46e6f6f7cb9d5e2371727d.png)
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(2)若
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解答题-证明题
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适中
(0.65)
【推荐1】如图,在
中,
,
是
的中点,以
为圆心,
为半径作圆,交
于点
,
是
的中点,延长
交
的延长线于点
,连接
.
(1)求证:
是
的切线.
(2)若
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解答题-证明题
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适中
(0.65)
【推荐2】如图,
是
的直径,
是
的弦,
,垂足是点
,过点
作直线
交
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,且
.
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(1)求证:
是
的切线;
(2)如果
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解答题-作图题
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【推荐1】已知:
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解答题-证明题
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(0.65)
【推荐2】如图1,在Rt△ABC中,∠ABC=90°,以AB为直径作⊙O,交AC于点F,F为
的中点,连接BD交于AC于点E.
![](https://img.xkw.com/dksih/QBM/2022/4/15/2958595551428608/2962421417025536/STEM/2eaee65a-08ef-4888-aa27-d6806c1daad9.png?resizew=310)
(1)求证: BE=BC.
(2)如图2,连接OF交BD于点G,取OB的中点H,连接GH,OD.若BC=5,BG=4,GH=
,求DE的长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d598504bacb6e8738d38f715a48bfdc2.png)
![](https://img.xkw.com/dksih/QBM/2022/4/15/2958595551428608/2962421417025536/STEM/2eaee65a-08ef-4888-aa27-d6806c1daad9.png?resizew=310)
(1)求证: BE=BC.
(2)如图2,连接OF交BD于点G,取OB的中点H,连接GH,OD.若BC=5,BG=4,GH=
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9658fb1429b9378cdeb5316778391c48.png)
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