如图,抛物线
交 x 轴于 A、B(A 左 B 右),交 y 轴于点 C,且tan∠ABC=1.
(2)点 P 为抛物线第一象限上一点,过点 P 作 PD∥y 轴,交 BC 于点 D,设点 P 的横坐标为 m,PD 的长为 d,求d 与 m 的函数关系式;
(3)在(2)的条件下,PD 平分∠BPF,PF 交 BC 于点 E,交 y 轴于点 F,作 DH⊥EF 于点 H,延长 HD 交 BP 于点 G,交抛物线于点 Q,若 DG=EF,求点 Q 的横坐标.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0fe67dcaf2dccfc0e043e672d7f8b4fd.png)
(2)点 P 为抛物线第一象限上一点,过点 P 作 PD∥y 轴,交 BC 于点 D,设点 P 的横坐标为 m,PD 的长为 d,求d 与 m 的函数关系式;
(3)在(2)的条件下,PD 平分∠BPF,PF 交 BC 于点 E,交 y 轴于点 F,作 DH⊥EF 于点 H,延长 HD 交 BP 于点 G,交抛物线于点 Q,若 DG=EF,求点 Q 的横坐标.
更新时间:2022-04-27 16:42:49
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【推荐1】如图,抛物线
经过点
和点
,与
轴交于点
,点
在直线
下方的抛物线上,过点
作
轴交
于点
,连接
,
,
,设点
的横坐标为
.
(1)求抛物线的解析式及点
的坐标;
(2)求线段
长度的最大值;
(3)当
的面积大于
的面积时,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d96dde9c4aad0536c069127df0d4b12f.png)
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(1)求抛物线的解析式及点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(2)求线段
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e430f13f42cf2d44aa0f0e20b959684f.png)
(3)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b044e1fc58f1da29ddf2fa8413aa5f05.png)
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【推荐2】如图,已知二次函数
的图象M经过
(
,0),
(2,
)两点且与
轴的另一个交点为
.
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(1)求该二次函数的解析式;
(2)点
是线段
上的动点(点G与线段
的端点不重合),若△AGB∽△ABC,求点G的坐标;
(3)设抛物线的对称轴为
,点![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5cedbe2eb3d2a0b1c195439aa23e9470.png)
是抛物线上一动点,当△ACD的面积为
时,点D关于
的对称点为E,能否在抛物线和
上分别找到点P、Q,使得以点D、E、P、Q为顶点的四边形为平行四边形. 若能,求出点P的坐标;若不能,请说明理由.
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(1)求该二次函数的解析式;
(2)点
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(3)设抛物线的对称轴为
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名校
【推荐1】如图,在
中,
,
是角平分线,
交
于
,
的外接圆
与边
相交于点
,过
作
的垂线交
于
,交
于
,交
于
,连接
.
(1)求证:
是
的切线;
(2)若
,
,求
的半径;
(3)在(2)的条件下,求
的长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87fd28b8b2bde9de5630a6106a6f762e.png)
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(1)求证:
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(2)若
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(3)在(2)的条件下,求
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【推荐2】如图1,抛物线
与y轴交于B点,与x轴交于A,C两点,直线BC的解析式为
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(1)求m与b的值;
(2)P是直线BC上方抛物线上一动点(不与点B,C重合),连接AP交BC于点E,交OB于点F.
①
是否存在最大值?若存在,求出
的最大值.并直接写出此时点E的坐标;若不存在,说明理由.
②当△BEF为等腰三角形时,直接写出点P的坐标.
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(1)求m与b的值;
(2)P是直线BC上方抛物线上一动点(不与点B,C重合),连接AP交BC于点E,交OB于点F.
①
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②当△BEF为等腰三角形时,直接写出点P的坐标.
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【推荐1】如图,抛物线y=-x2+bx+c的顶点为D,与x轴交于A(-1,0)、B(3,0),与y轴交于点C.
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(1)求该抛物线的解析式;
(2)若点P为线段BC上的一点(不与B、C重合),PM∥y轴,且PM交抛物线于点M,交x轴于点N,当四边形OBMC的面积最大时,求△BPN的周长;
(3)在(2)的条件下,当四边形OBMC的面积最大时,在抛物线的对称轴上是否存在点Q,使得△CNQ为直角三角形?若存在,直接写出点Q的坐标.
![](https://img.xkw.com/dksih/QBM/2015/9/11/1573911508680704/1573911514914816/STEM/26a54ce9c31247718c9ac8d76aebe4e3.png)
(1)求该抛物线的解析式;
(2)若点P为线段BC上的一点(不与B、C重合),PM∥y轴,且PM交抛物线于点M,交x轴于点N,当四边形OBMC的面积最大时,求△BPN的周长;
(3)在(2)的条件下,当四边形OBMC的面积最大时,在抛物线的对称轴上是否存在点Q,使得△CNQ为直角三角形?若存在,直接写出点Q的坐标.
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【推荐2】如图,在平面直角坐标系中,点
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交
轴于点
、
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轴于点
.
(1)求点
的坐标;
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是第一象限抛物线上的一点,连接
交
轴于点
,设点
的横坐标为
,线段
的长为d,求d与
之间的函数解析式(不要求写出自变量
的取值范围);
(3)在(2)的条件下,当
时,点
在抛物线上,且横坐标为
,连接
交
轴于点
,连接
交线段
于点
,点
为线段
的中点,连接
,
,若
,求
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
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![](https://img.xkw.com/dksih/QBM/editorImg/2023/8/23/9fa3d80e-862c-4ffb-891f-46f3e8739269.png?resizew=527)
(1)求点
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(2)点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36a1b09c653185842513e24ebba60bb3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4eedae8d316c76e3d0b451256de03fb9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36a1b09c653185842513e24ebba60bb3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36a1b09c653185842513e24ebba60bb3.png)
(3)在(2)的条件下,当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8a53cfc984de5d66c09ed7c09116a91.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97add95cc99b7846691dbdd91ef0f3bf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/274cf35acb4a1748d15c39d15a9bea7b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cae70b8a9d2d2e96dea62c00ced04b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73465a1f9aa03481295bf6bd3c6903ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06e322e0c87479bba874db9ae9ba36b5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/77a7e4a6765ce78b05ee97764771e01f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/589786dd7c3a2679c3230b671cd232d6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cae1f5d57400a54d6942ee140893dc05.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04331b5255108a9c9ce87f471b5b7adf.png)
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