如图,在正方形ABCD中,若AD=5,在边AB上取点E,使AE=1,又以点D为圆心,DE作⊙D,交BC的延长线于点F,连接EF交DC于点G.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/10/b5d41eb6-b2a4-41cb-ad08-54b420015ad3.png?resizew=140)
(1)求证:∠ADE=∠CDF;
(2)请求出EF的长;
(3)请求出GC的长.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/10/b5d41eb6-b2a4-41cb-ad08-54b420015ad3.png?resizew=140)
(1)求证:∠ADE=∠CDF;
(2)请求出EF的长;
(3)请求出GC的长.
更新时间:2022-06-02 14:07:58
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【推荐1】如图,在
中,D是
边上的中点,
,
,垂足分别是点E,F且
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(1)
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【推荐2】已知:如图,在
中,
,
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,垂足为点
,
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(1)求
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【推荐1】在数学课上,老师提出问题“尺规作图:作已知线段
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【推荐2】如图所示,AB是⊙O的一条弦,ODAB,垂足为C,交⊙O于点D,点E在⊙O上.
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【推荐2】已知四边形
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【推荐1】如1图,
是
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【推荐2】中考新考法:跨物理并联电路,请阅读下列材料,完成相应的任务:
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依据1:____________;
依据2:____________;
(2)如图②,两个电阻并联在同一电路中,已知
千欧,
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的线段长;
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有这样一个题目:设有两只电阻,分别为![]() ![]() ![]() 我们可以利用公式 ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() 证明: ![]() ![]() 又 ![]() ![]() ![]() 同理可得: ![]() ![]() ![]() ![]() |
(1)上述证明过程中的“依据1”和“依据2”分别是指:
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