已知,矩形ABCD中,延长BC至E,使BE = BD,F为DE的中点,连结AF、CF.
![](https://img.xkw.com/dksih/QBM/2013/6/14/1573663228002304/1573663234334720/STEM/675a78d1b6c446a8bd0b4fd0d2348135.png)
(1)若AB = 3,AD = 4,求CF的长;
(2)求证:∠ADB = 2∠DAF.
![](https://img.xkw.com/dksih/QBM/2013/6/14/1573663228002304/1573663234334720/STEM/675a78d1b6c446a8bd0b4fd0d2348135.png)
(1)若AB = 3,AD = 4,求CF的长;
(2)求证:∠ADB = 2∠DAF.
更新时间:2016-12-05 18:08:57
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【推荐1】菱形ABCD中,E为对角线BD边上一点.
当
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【推荐2】已知:如图所示,
是
直径,
,C在
上,连接
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延长线上取一点E,使
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(1)判断
的形状并证明;
(2)过D作
于F,射线OF交
于G,作
于H:
①请你按照要求补全图形;
②探索
与
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【推荐1】如图,长方形纸片ABCD放置在平面直角坐标系中,A与原点O重合.B、D分别在x轴和y轴上,
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【推荐1】如图所示,在RtΔABC中,∠ACB=90°,过点C的直线MN∥AB,D为AB的中点,过点D作DE⊥BC,交直线MN于E,垂足为F,连接CD、BE.
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