如图,已知Rt△ABC,∠BAC=90°,在△ABC的外部分别以线段AB、AC、BC为边作正方形ABDE、正方形ACFG、正方形BCPQ,连接AQ、DC,交点为M.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/29/f58b37cc-f813-4f61-aee5-8c607194715b.png?resizew=486)
(1)判断线段AQ、DC的关系,并说明理由;
(2)如图①,过点A作AI⊥PQ,垂足为I,与边BC交于点H,证明:S矩形BHIQ=S正方形ABDE;
(3)直接写出S正方形ABDE,S正方形ACFG,S正方形BCPQ的数量关系;
(4)如图②,在Rt△ABC中,若∠ABC=45°,AC
,直接写出线段AQ的长.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/29/f58b37cc-f813-4f61-aee5-8c607194715b.png?resizew=486)
(1)判断线段AQ、DC的关系,并说明理由;
(2)如图①,过点A作AI⊥PQ,垂足为I,与边BC交于点H,证明:S矩形BHIQ=S正方形ABDE;
(3)直接写出S正方形ABDE,S正方形ACFG,S正方形BCPQ的数量关系;
(4)如图②,在Rt△ABC中,若∠ABC=45°,AC
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ae65bdb69940a67a18d56ff02060b22.png)
更新时间:2022-08-25 21:35:01
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解答题-作图题
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【推荐1】已知∠MON=120°,点A、B分别在OM、ON上,OA<OB,连接AB,在AB上方作等边△ABC,点D是BO延长线上一点,且AB=AD,连接AD.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/29/5c5f51d5-b90d-404b-ae18-5f3011e1f06b.png?resizew=396)
(1)补全图形,并直接写出∠CAO和∠CBO的数量关系;
(2)连接CO,判断∠COM和∠CON是否相等?请你说明理由;
(3)连接CD,CD交OM于点F,请写出一个∠DAB的值,使CD=OB+OC一定成立,并说明理由.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/29/5c5f51d5-b90d-404b-ae18-5f3011e1f06b.png?resizew=396)
(1)补全图形,并直接写出∠CAO和∠CBO的数量关系;
(2)连接CO,判断∠COM和∠CON是否相等?请你说明理由;
(3)连接CD,CD交OM于点F,请写出一个∠DAB的值,使CD=OB+OC一定成立,并说明理由.
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【推荐2】在
中,
,
,
,将
绕点
顺时针旋转一定的角度
得到
,点
,
的对应点分别是
,
,连接
.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/24/53ad41b6-1bca-47b2-a69f-2f2242dc0809.jpg?resizew=446)
(1)如图
,当点
恰好在
上时,求
的大小;
(2)如图
,若
,点
是
的中点,判断四边形
的形状,并证明你的结论.
(3)如图
,若点
为
中点,
求证:
、
、
三点共线.
求
的最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd967903ed5a6f640a5b801ec8be0070.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed10df4140819d5451773a45de66201b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fb01d2b57580731c8b807ac8cffc8ba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bb5b12692517a39c320f99a479eb055.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/321370fe42bc1216902ea19fbd2a5979.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/24/53ad41b6-1bca-47b2-a69f-2f2242dc0809.jpg?resizew=446)
(1)如图
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bdaa19de263700a15fcf213d64a8cd57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23dc2d2dd56fcc67698c45a6e0e48f80.png)
(2)如图
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97cf714ffb3fd5917a76b191640b55fe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/af045d2542c40f955a9de356b9b088c4.png)
(3)如图
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e1c9ae241fd78126274c65e17990c88.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5c650fe55b7603f106c53ca2423451c6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cae70b8a9d2d2e96dea62c00ced04b9.png)
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解题方法
【推荐1】[方法储备]如图1,在
中,
为
的中线,若
,
,求
的取值范围.中线倍长法:如图2,延长
至点
,使得
,连结
,可证明,由全等得到
,从而在
中,根据三角形三边关系可以确定
的范围,进一步即可求得
的范围.
在上述过程中,证明
的依据是______,
的范围为______;
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/6/105e9b4f-410f-4b19-9cc1-b739f8a845a4.png?resizew=452)
[思考探究]如图3,在
中,
,
为
中点,
、
分别为
、
上的点,连结
、
、
,
,若
,
,求
的长;
[拓展延伸]如图4,
为线段
上一点,
,分别以
、
为斜边向上作等腰
和等腰
,
为
中点,连结
,
,
.
①求证:
为等腰直角三角形;
②若将图4中的等腰
绕点
转至图5的位置(
,
,
不在同一条直线上),连结
,
为
中点,且
,
在
同侧,连结
,
.若
,
,求
和
的面积之差.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db54223bb3fc2fe2497213a4d1f94827.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bb5b12692517a39c320f99a479eb055.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e65a3e478bb87d094e3a0af30dd10ae8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db54223bb3fc2fe2497213a4d1f94827.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db54223bb3fc2fe2497213a4d1f94827.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b47d30006e2463739e4f7de4bc7f40fc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fca905896e0786da8c85df0aa294fe3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/661ff55b5ebbadfb600989af3cfce2fd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db54223bb3fc2fe2497213a4d1f94827.png)
在上述过程中,证明
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6cf5c3b03a2fde56e589166b110103dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db54223bb3fc2fe2497213a4d1f94827.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/6/105e9b4f-410f-4b19-9cc1-b739f8a845a4.png?resizew=452)
[思考探究]如图3,在
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed10df4140819d5451773a45de66201b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be2e2c0d4ac2bd79f6cea7a9b1a50662.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9ce6c0e9de83f2e64ae33609fc08459d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27e887de7300ee5cb4d40ddfcac9a686.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adc90c2d45477e166b02359525f40aa6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09d27bd71d79cb19eb554175e4ef0867.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
[拓展延伸]如图4,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5e95be88bc79b3c7e72d349c4cb3c88d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10ce5d6ca24e249f7172e51c154509b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d288a8ece64aaa06264a23a7c17d3c8e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15a424b50eaeafa6f302ffd95476cb86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b46c607b3deac746c0ef3389ad8f65c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
①求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9825e881728e22d0b8d4dab50854c433.png)
②若将图4中的等腰
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d288a8ece64aaa06264a23a7c17d3c8e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15a424b50eaeafa6f302ffd95476cb86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b46c607b3deac746c0ef3389ad8f65c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ecf7679c8b4b1e442ce4286d4b0e9c32.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5fbd8e8c759858fb3d3132605d44e865.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d50244defdb202cc420e1d6a910241c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82fd5e259868f7f38577bc1f2a41e4c5.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/6/a92e025d-9a44-4769-b4b6-3641a1adc5a6.png?resizew=395)
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【推荐2】猜测、推断型探究题目:
观察发现:
(1)如图,分别以Rt△ABC三边(可用a、b、c表示)向外作三个正方形,其面积分别用S1、 S2、 S3表示,我们可以通过拼图或数格子,易得:S1= S2+ S3.
推理验证:
![](https://img.xkw.com/dksih/QBM/2020/10/15/2571612117057536/2573098373259264/STEM/6d272b432ecb46739107d92a3a1c224c.png?resizew=138)
(2)如图,分别以Rt△ABC三边 (可用a、b、c表示)为直径向外作三个半圆,其面积分别用S1、 S2、 S3表示,那么S1、 S2、 S3之间有什么关系?说明理由.
动手操作:
![](https://img.xkw.com/dksih/QBM/2020/10/15/2571612117057536/2573098373259264/STEM/05c283fb84d5459784836b061e297dc8.png?resizew=151)
(3)分别以Rt△ABC三边 (可用a、b、c表示)向外作不同于(1)(2)的图形,其面积分别用S1、 S2、 S3表示,使S1、 S2、 S3仍成立.
观察发现:
(1)如图,分别以Rt△ABC三边(可用a、b、c表示)向外作三个正方形,其面积分别用S1、 S2、 S3表示,我们可以通过拼图或数格子,易得:S1= S2+ S3.
推理验证:
![](https://img.xkw.com/dksih/QBM/2020/10/15/2571612117057536/2573098373259264/STEM/6d272b432ecb46739107d92a3a1c224c.png?resizew=138)
(2)如图,分别以Rt△ABC三边 (可用a、b、c表示)为直径向外作三个半圆,其面积分别用S1、 S2、 S3表示,那么S1、 S2、 S3之间有什么关系?说明理由.
动手操作:
![](https://img.xkw.com/dksih/QBM/2020/10/15/2571612117057536/2573098373259264/STEM/05c283fb84d5459784836b061e297dc8.png?resizew=151)
(3)分别以Rt△ABC三边 (可用a、b、c表示)向外作不同于(1)(2)的图形,其面积分别用S1、 S2、 S3表示,使S1、 S2、 S3仍成立.
![](https://img.xkw.com/dksih/QBM/2020/10/15/2571612117057536/2573098373259264/STEM/0a8ab85fb5cd41d3a9b39766ba6c62b7.png?resizew=123)
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【推荐1】如图,在矩形ABCD中,E是BC上一点,连接AE,将矩形沿AE翻折,使点B落在CD边F处,连接AF,在AF上取一点O,以点O为圆心,OF为半径作⊙O与AD相切于点P.AB=6,BC=![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adbd3e8cf8325999cde03adf845d3dd0.png)
![](https://img.xkw.com/dksih/QBM/2020/1/14/2376972482379776/2377739295080448/STEM/9d8ab7aa4d964b80ba150d0d4e0cfbd0.png?resizew=139)
(1)求证:F是DC的中点.
(2)求证:AE=4CE.
(3)求图中阴影部分的面积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adbd3e8cf8325999cde03adf845d3dd0.png)
![](https://img.xkw.com/dksih/QBM/2020/1/14/2376972482379776/2377739295080448/STEM/9d8ab7aa4d964b80ba150d0d4e0cfbd0.png?resizew=139)
(1)求证:F是DC的中点.
(2)求证:AE=4CE.
(3)求图中阴影部分的面积.
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解题方法
【推荐2】如图,点P为正方形ABCD的对角转AC上一动点,过点P作PE⊥PB交射线DC于点E.
![](https://img.xkw.com/dksih/QBM/2021/8/22/2791483608965120/2798084524818432/STEM/3d2c6cbb3bad49f6b37e49f59396dba4.png?resizew=482)
(1)如图1,当点E在边CD上时,求证:PB=PE;
(2)如图2,当点E在DC的延长线上时,探求线段PA、PC、CE的数量关系并加以证明;
(3)如图3,在(1)的条件下,连接BE交AC于点F,若正方形ABCD的边长为4,当点E为CD的中点,则PF= (请直接写出结果).
![](https://img.xkw.com/dksih/QBM/2021/8/22/2791483608965120/2798084524818432/STEM/3d2c6cbb3bad49f6b37e49f59396dba4.png?resizew=482)
(1)如图1,当点E在边CD上时,求证:PB=PE;
(2)如图2,当点E在DC的延长线上时,探求线段PA、PC、CE的数量关系并加以证明;
(3)如图3,在(1)的条件下,连接BE交AC于点F,若正方形ABCD的边长为4,当点E为CD的中点,则PF= (请直接写出结果).
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