如图,点P是正方形ABCD的对角线BD上一点,PE⊥BC于点E,PF⊥CD于点F,连接EF给出下列五个结论:①AP =EF;②AP⊥EF;③△APD一定是等腰三角形;④∠PFE=∠BAP;⑤PD=
EC.其中正确结论的序号是( ).
![](https://img.xkw.com/dksih/QBM/2017/12/21/1843385471918080/1843933476036608/STEM/bf9ce2cf313e4cdf8a09c1ddb9eb9a20.png?resizew=113)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf298f00799cbf34b4db26f5f63af92f.png)
![](https://img.xkw.com/dksih/QBM/2017/12/21/1843385471918080/1843933476036608/STEM/bf9ce2cf313e4cdf8a09c1ddb9eb9a20.png?resizew=113)
A.①②④⑤ | B.①②④ | C.④⑤ | D.①②⑤ |
更新时间:2016-12-05 23:28:01
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【推荐1】如图,等边三角形
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