如图,正方形ABCD的边长为6,点E是BC的中点,连接AE与对角线BD交于点G,连接CG并延长,交AB于点F,连接DE交CF于点H,连接AH.以下结论:①CF⊥DE;②
;③AD=AH;④GH=
,其中正确结论的序号是__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eafa7f72b2b5d9ff45139bf92f75136d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9df4781fe3dec338f2abfe833f5f0615.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/8/30/e18aad78-e3f4-4e31-a34f-54718ad26b1e.png?resizew=156)
更新时间:2020-06-27 10:36:35
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【推荐1】如图,
中,
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【推荐2】如图,在平行四边形ABCD中,∠BAD=60°,延长AD至点E使得AE=AB,连接BE交CD于点F,连结并延长AF,交CE于点G.下列结论:①△BAD≌△EBC;②BD=AF;③BD⊥AG;④若AD=2DE,则
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【推荐2】如图,在
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