如图,在△ABC中,∠ACB=90°,∠A<∠B,点D为AB边上一点且不与A、B重合,将△ACD沿CD翻折得到△ECD,直线CE与直线AB相交于点F.若∠A=α,当△DEF为等腰三角形时,∠ACD=__________________ .(用α的代数式表示∠ACD)
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更新时间:2021-09-10 13:23:16
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【推荐1】如图,∠ABC=∠ACB,AD、BD、CD分别平分△ABC的外角∠EAC、内角∠ABC、外角∠AFC,以下结论:①AD∥BC;②∠ACB=2∠ADB;③∠ADC=90°—∠ABD;④∠BDC=
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【推荐2】如图,AB∥CD,∠C=20°,∠A=55°,则∠E=_____ .
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【推荐1】如图,等腰三角形ABC的底边BC长为2,面积是4,腰AC的垂直平分线 EF分别交AC,AB边于E,F 点,若点D 为BC边的中点,点M 为线段EF上一动点,则△CDM 周长的最小值为__________ .
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