在课堂上,老师布置了一道思考题:如图1,点M,N分别在正三角形ABC的BC,CA边上,且BM=CN,AM,BN交于点Q.
![](https://img.xkw.com/dksih/QBM/2021/12/13/2871419137089536/2877147851309056/STEM/b765c3cd-03a3-47d1-a153-a08f19f71141.png?resizew=334)
(1)求证:∠BQM=60°;
(2)如图2,若将图1中的点M,N分别移动到BC、CA的延长线上,且BM=CN,连接BN,AM,MA的延长线交BN于点Q(1)中的结论∠BQM=60°是否仍然成立?请说明理由.
![](https://img.xkw.com/dksih/QBM/2021/12/13/2871419137089536/2877147851309056/STEM/b765c3cd-03a3-47d1-a153-a08f19f71141.png?resizew=334)
(1)求证:∠BQM=60°;
(2)如图2,若将图1中的点M,N分别移动到BC、CA的延长线上,且BM=CN,连接BN,AM,MA的延长线交BN于点Q(1)中的结论∠BQM=60°是否仍然成立?请说明理由.
更新时间:2021-12-21 09:15:11
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【推荐1】如图,已知
,点B、C分别是射线
,
上的两个点(B,C均不与点A重合),点P是
内部的一点(P、B、C三点不在一直线上)
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(1)若
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①如图1,
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的度数;
②如图2,
,
,垂足分别是B,C,求
的度数.
(2)连接
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![](https://img.xkw.com/dksih/QBM/editorImg/2023/4/28/2d171898-997d-415f-bd60-146b7faac4e6.png?resizew=495)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08fddda4936a9be50e32b18b4c79e8b3.png)
①如图1,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68cdb43302f8924eebcc1e3595652a78.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef0433f8116768b42642a7f7e5977ce6.png)
②如图2,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/186e5e7efe51fd25b9e38dc0fa23de9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca7f962fff7a425e7f23625408c9d964.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef0433f8116768b42642a7f7e5977ce6.png)
(2)连接
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d2be49c37e30a3ced0364c3e74d8c687.png)
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【推荐2】如图1,
,直线
交
于点E,交
于点F,点G在
上,点P在直线
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;
(2)连接
,若
平分
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,
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的度数;
(3)如图2,若
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(3)如图2,若
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【推荐2】如图,在△ABC中,∠C=90°,∠CAD=∠BAD,DE⊥AB于E,点F在边AC上,连接DF.
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【推荐1】如图.在等边△ABC中,∠ABC与∠ACB的平分线相交于点O,且
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【推荐2】如图,
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