如图,任意画一个∠A=60°的△ABC,再分别作△ABC的两条角平分线BE和CD,BE和CD相交于点P,连接AP,有以下结论:①∠BPC=120°;②AP平分∠BAC;③点P到边AB,AC,BC的距离相等;④BD+CE=BC;⑤
,其中错误的个数是( )个.
![](https://img.xkw.com/dksih/QBM/2022/1/16/2895439927713792/2896442520535040/STEM/8dcf82e2-1c1d-483c-afcf-7bb0fd875b7e.png?resizew=177)
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A.0 | B.1 | C.2 | D.3 |
更新时间:2022-01-17 15:30:18
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