如图,直线
与x轴、y轴分别相交于B、C,经过B、C两点的抛物线
与x轴另一交点为A,顶点为P,且对称轴是直线
,
![](https://img.xkw.com/dksih/QBM/2022/12/29/3141091602309120/3144070695141376/STEM/3f4e69aba8fa4ca0923b8afb1eb52993.png?resizew=221)
(1)求抛物线解析式;
(2)连接
,求
.
(3)在x轴上是否存在点Q,使得以点P、B、Q为顶点的三角形与
相似,若存在,请求出Q点坐标;若不存在,说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae652daf6059ff386f99bef2210518c5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a90385c676848de67293e3ed6bc000fe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/707ea658f3a9359f5740d5aab48f7948.png)
![](https://img.xkw.com/dksih/QBM/2022/12/29/3141091602309120/3144070695141376/STEM/3f4e69aba8fa4ca0923b8afb1eb52993.png?resizew=221)
(1)求抛物线解析式;
(2)连接
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c3d08f0ab6e573253450e03427e13db1.png)
(3)在x轴上是否存在点Q,使得以点P、B、Q为顶点的三角形与
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/90b40c2b0ab8e1cfe5112d428b4b829f.png)
更新时间:2023-01-02 12:11:06
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【推荐1】如图,已知抛物线y=﹣x2+bx+c与x轴交于A、B两点,交y轴于点C,已知A(﹣1,0)对称轴是直线x=1.
(1)求抛物线的解析式及点C的坐标;
(2)动点M从点O出发,以每秒2个单位长度的速度向点B运动,过M作x轴的垂线交抛物线于点N,交线段BC于点Q.设运动时间为t(t>0)秒.
①若
AOC与
BMN相似,请求出t的值;
②
BOQ能否为等腰三角形?若能,求出t的值.
(1)求抛物线的解析式及点C的坐标;
(2)动点M从点O出发,以每秒2个单位长度的速度向点B运动,过M作x轴的垂线交抛物线于点N,交线段BC于点Q.设运动时间为t(t>0)秒.
①若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ce4cba95fc7d4853a243f8e3fb20ce70.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ce4cba95fc7d4853a243f8e3fb20ce70.png)
②
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ce4cba95fc7d4853a243f8e3fb20ce70.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/6/28/88b8b94e-af23-4fd6-b664-8004d7a6f8d3.png?resizew=640)
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【推荐2】如图,在平面直角坐标系中,点A(1,0),点B(0,3),点C在x轴的负半轴上,∠BCA=45°,CD⊥AB,垂足为点D,CD与y轴交于点E. 点A,B,C分别在二次函数图象上.
(1)求二次函数表达式;
(2)连接AE并延长交二次函数的图象于点F,请你求出点F的坐标;
(3)设二次函数的对称轴与x轴的交点为H,在直线AF上有一动点M,连接MH,将线段MH 绕点M顺时针旋转90°得到线段MN,连接HN,AN,求NH+AN的最小值.
(1)求二次函数表达式;
(2)连接AE并延长交二次函数的图象于点F,请你求出点F的坐标;
(3)设二次函数的对称轴与x轴的交点为H,在直线AF上有一动点M,连接MH,将线段MH 绕点M顺时针旋转90°得到线段MN,连接HN,AN,求NH+AN的最小值.
![](https://img.xkw.com/dksih/QBM/2021/6/1/2733755874623488/2737882161528832/STEM/59f1575c-0ade-43a9-91f4-70ff53ee478b.png)
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【推荐1】已知:如图,在正方形ABCD中,联结BD,E是边AB上一点,BF⊥DE,垂足为点F,且EF•BD=BE•BF.
(1)求证:∠ADE=∠BDE;
(2)延长DF与CB的延长线交于点G,求证:BG=BC+AE.
(1)求证:∠ADE=∠BDE;
(2)延长DF与CB的延长线交于点G,求证:BG=BC+AE.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/25/cb1ce5e9-61d5-4432-bec9-1c844fc3b18f.png?resizew=166)
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【推荐2】已知抛物线y=x2+bx+c经过点A(3﹣m,4),且过点B(3+m,4),A在B的左侧,顶点为P.
(1)求b的值;
(2)当c=4时,求sin∠APB;
(3)抛物线y=x2+bx+c上是否存在点Q,使得四边形OPQA是平行四边形?若存在,请求出点Q的坐标;若不存在,请说明理由.
(1)求b的值;
(2)当c=4时,求sin∠APB;
(3)抛物线y=x2+bx+c上是否存在点Q,使得四边形OPQA是平行四边形?若存在,请求出点Q的坐标;若不存在,请说明理由.
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【推荐1】如图1,已知二次函数
:
的图像与x轴交于点
,B(4,0)两点,与y轴交于点C,
,如图1
![](https://img.xkw.com/dksih/QBM/2022/5/31/2991183173345280/2992497256816640/STEM/8096d6a9-b1d3-4ee8-a31d-8e1692484284.png?resizew=608)
(1)求二次函数
的表达式:
(2)将
沿x轴对称,再沿x轴正方向向右平移2个单位长度,得到新抛物线
,直线
轴,分别交
,
于点M,N,如图2,求线段MN的最大值:
(3)在抛物线
上是否存在点P,使得
?若存在,求出P的横坐标;若不存在,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8352b2e643a7ce605334f1b0e572bfb0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0929421a6188c3122442866b0b85a5e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bcd3fd00798e7ec50afafe7fa7a4f42e.png)
![](https://img.xkw.com/dksih/QBM/2022/5/31/2991183173345280/2992497256816640/STEM/8096d6a9-b1d3-4ee8-a31d-8e1692484284.png?resizew=608)
(1)求二次函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
(2)将
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f3ffe7abc59e2f65d827c8eab8d36a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/52cbeb9b1c1d637b903cf3e5c7f730f6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f3ffe7abc59e2f65d827c8eab8d36a.png)
(3)在抛物线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8aab4e7e4d2ac551e7c3046e2a22cd0a.png)
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【推荐2】如图1,已知点
为抛物线
上一动点,以
为顶点,且经过原点
的抛物线,记作“
”,设其与
轴另一交点为
,点
的横坐标为
.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/3/22/77518db8-ef34-4c6b-92d2-0f67017d9b6d.png?resizew=367)
(1)①当
为直角三角形时,
______;
②当
为等边三角形时,求此时“
”的解析式;
(2)如图2,若
点的横坐标分别为1,2,3,…
(
为正整数)时,抛物线“
”分别记作“
”、“
”,…“
”,设其与
轴另外一交点分别为
,
,
,…
,过
,
,
,…
作
轴的垂线,垂足分别为
,
,
,…
.
①
的坐标为______;
=______;(用含
的代数式来表示)
②当
时,求
的值.
(3)是否存在这样的
,使得
,若存在,求
的值;若不存在,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e30700a1d4c40901786b9c6c7301162.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c6cfbe589feebb9e804d167667e4645.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/3/22/77518db8-ef34-4c6b-92d2-0f67017d9b6d.png?resizew=367)
(1)①当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d3991001f80af2716b605efe2d7641d8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6c57bbef89a37f1a3808c0ceeac0c22.png)
②当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d3991001f80af2716b605efe2d7641d8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c6cfbe589feebb9e804d167667e4645.png)
(2)如图2,若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c6cfbe589feebb9e804d167667e4645.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3df25ba8602080ceaab4e7f64d3117d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0d94a26c6992eb86a14040da31b36fac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1362c1623d29ba88211310c83b3e463b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a18722354086c42e62334983fc50eb6a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd3b9e816b14051f785aa5aae72b8eed.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04b56e44e4f0424a2b7a45567120a2e4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d3cfeacc29e6a61c5b3b4e439c0a91df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2708fa6298e52f617383efc175b71ddc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b9cb8e6ff801523b0304576cd69fd2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/797e67927616b141ed7c6b83f8b6f4fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf83e20035c3afd6d26ebfd53d768a70.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/86163e76653de1f383788b741fb64a8b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9e1fae01485740cbb48b5c79f1185b54.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/301a6928b2b289ace1e9e5c8420610ab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87bd7d18f67e90a7c37fad4252e43c9d.png)
①
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf83e20035c3afd6d26ebfd53d768a70.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/337d0dc1076cfdb02ffb40bf4dac0d90.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
②当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5dca25277350df9bf39533d4acc7e65.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
(3)是否存在这样的
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d3cfeacc29e6a61c5b3b4e439c0a91df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34bce7bd729b50c992b25cba0c6a496a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
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【推荐1】如图1,经过原点O的抛物线y=ax2+bx(a≠0)与x轴交于另一点A(
,0),在第一象限内与直线y=x交于点B(2,t).
(1)求这条抛物线的表达式;
(2)在第四象限内的抛物线上有一点C,满足以B,O,C为顶点的三角形的面积为2,求点C的坐标;
(3)如图2,若点M在这条抛物线上,且∠MBO=∠ABO,在(2)的条件下,是否存在点P,使得△POC∽△MOB?若存在,求出点P的坐标;若不存在,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a4b8503f4706b8321e4e79a87eadea84.png)
(1)求这条抛物线的表达式;
(2)在第四象限内的抛物线上有一点C,满足以B,O,C为顶点的三角形的面积为2,求点C的坐标;
(3)如图2,若点M在这条抛物线上,且∠MBO=∠ABO,在(2)的条件下,是否存在点P,使得△POC∽△MOB?若存在,求出点P的坐标;若不存在,请说明理由.
![](https://img.xkw.com/dksih/QBM/2018/3/27/1911170966364160/1914967550754816/STEM/84ad563febae435585cc6ee48a817d09.png?resizew=357)
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【推荐2】如图1,在平面直角坐标系xOy中,直线y=x+4与坐标轴分别交于A、C两点,抛物线y=−x2+bx+c经过A、C两点,与x轴的另一交点为B点.
(1)点A的坐标是 ,点C的坐标是 ,抛物线的解析式是 ;
(2)若点P是该抛物线的对称轴上的一个动点,连接PA,PC,设点P的纵坐标表示为m,试探究:当m为何值时,
的值最大?并求出这个最大值;
(3)如图2,点D为线段AC上一动点,过点D作EH⊥x轴于点H,交抛物线于点E.
①当DE=3时,求点H的坐标;
②连接CE,是否存在点D,使得△CDE和△DAH相似?若存在,求此点D坐标;若不存在,说明理由.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/9/19/0763fc0d-f244-41a0-b4bb-4792b9249f9f.png?resizew=261)
(1)点A的坐标是 ,点C的坐标是 ,抛物线的解析式是 ;
(2)若点P是该抛物线的对称轴上的一个动点,连接PA,PC,设点P的纵坐标表示为m,试探究:当m为何值时,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16616a1c519815e7260b67c4b3b33ad4.png)
(3)如图2,点D为线段AC上一动点,过点D作EH⊥x轴于点H,交抛物线于点E.
①当DE=3时,求点H的坐标;
②连接CE,是否存在点D,使得△CDE和△DAH相似?若存在,求此点D坐标;若不存在,说明理由.
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